Rutgers/Lucent ALLIES IN TEACHING MATHEMATICS AND TECHNOLOGY Grant
Using technology not simply to do things better, but to do better things.


OTHER STUDENT RESPONSES:
Phone-O-Graph Phollies


Answer #1: Plan C will be cheapest over 100 calls, but under 100 calls means that Plan B is cheaper than Plan A.

Explanation:

Plan A=12.46+.13x
Plan B=5.17+.24x
Plan C=24.50

I just plugged in numbers for x and see how it came out.


Answer #2: Plan A would be the best plan for us.

Explanation: We made a diagram which showed the monthly cost with the additional price of 90 phone calls. A total monthly cost for plan A with these 90 phone calls would be $24.16. A total monthly cost for plan B with these additional 90 calls would be $26.77. A total monthly cost for plan C would be 24. 50.

The only reason that we chose plan A over Plan C was because neither of us, nor ther average teenager, is likely to go over 90 phone calls a month. However, a more fickle, more talkative teenager would be more likely to suceed with plan C because you are aware of what you must pay at the end of the month.

Our graph proves that in a situation with 2 phone calls per day on a long month would favor Plan B. But since we average 3 phonecalls per day, PLan A would be the best plan for us.


Answer#3: I think that plan "b" would be best for me because i don't really make 80 calls a month ,so this is the best plan because i usually make about 60 or 70 calls a month and with plan "b" it would come out to $19.57 to $21.97.

Explanation: The process i used was that i first did a function chart for the equation for both plan "a" and "B" which are a= $12.46+$.13(x)=(total) and for "b"= $5.17+$.24(x)=(total) i multiplied by tens.

Later i did a double line graph that shows how plan a and plan b intersect when you make about 70 calls.


Answer #4: "B" IS MORE ECONOMICAL WHEN YOU MAKE A SMALL AMOUNT OF CALLS IE: 10-15 CALLS. "C" IS MORE ECONOMICAL WHEN YOU MAKE A LARGE AMOUNT OF CALLS IE: 100-200.

Explanation: BEFORE WE STARTED TO SOLVE THIS PROBLE, WE DECIDED TO USE EITHER 10 CALLS OR 100 CALSS. FIRST, TO SOLVE THE 10 CALL PROBLEM, WE TOOK THE AMOUNT PLAN A CHARGED FOR EACH CALL AND MULTIPLIED IT BY 10. WE GOT $13.76. THEN WE DID THE SAME FOR B. $7.57. FOR C WE GOT 24.50,
BECAUSE WE DIDN'T NEED TO ADD ANY MINUTE CALLS. IT TURNED OUT THAT B WAS MORE ECONOMICAL FOR SMALL AMOUNTS OF CALLS. FOR THE 100 CALLS PROBLEM, WE DID THE SAME EXCEPT MULTIPLIED IT BY 100. FOR A WE GOT 25.46. FOR BH WE GOT 29.17. FOR C WE GOT 24.50.


Answer #5: Plan B is the best choice Because it has the cheapest price: $119.64

Explanation: For 1 year= 12 months 1 month= 20 calls
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
12(12.46) + 12[20(13)]=A
$149.52 + $31.20=A
$180.72=A

BBBBBBBBBBBBBBBB
12(5.17) + 12[20(24)]=B
$62.04 + $57.60=B
$119.64=B

CCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
12(24.50)=C
$294.00=C

B is more preferable, because it saves you more than $180.72 and $294.00.


Answer#6: For plan A, the equation is 12.46+13c=d
For plan B, the equation is 5.17+24c=d
For plan C, the equation is 24.5+0c=d


Explanation: When I looked at the problem, I thought that it would be neat to make a graph to show the comparison between the rates. On the Y axis I the number of phone calls and on the X axis I put down the monthly rate. By doing this, I had many different rates to compare.
I found that plan C is the best plan for people who are going to make a lot of local calls. Plan B is for people who are not going to make a lot of local calls and plan A is for people who are in between Plan A and B. When I made the equations, I took the rate for each local call and attached the varible to it to show that it could be any number divisible by the rate.



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