system (04:46:15:102 PM): Mod1 entered the Algebra2 chat room. system (04:46:46:280 PM): jon entered the Algebra2 chat room. Mod1 (04:46:58:587 PM): Hi again, Jon jon (04:47:00:548 PM): hello Mod1 (04:47:06:883 PM): Sorry for the delay. jon (04:47:09:838 PM): its ok Mod1 (04:47:15:974 PM): It is better if we do it in a different room. jon (04:47:20:254 PM): yea Mod1 (04:47:30:503 PM): so tell me your problem, again? jon (04:47:47:233 PM): 5x sq.+100=0 jon (04:47:59:233 PM): it says to solve the inequality Mod1 (04:48:20:304 PM): like that? jon (04:48:41:730 PM): i dont know how to do the square sings jon (04:48:45:949 PM): signs* jon (04:48:48:726 PM): yea Mod1 (04:49:04:903 PM): use the symbol on top of the 6 key. x^2 Mod1 (04:49:14:852 PM): is x squared jon (04:49:15:249 PM): alright,thank you jon (04:49:18:799 PM): yes Mod1 (04:49:38:674 PM): so, you need to solve the "inequality", but which inequality? jon (04:50:06:513 PM): it just says to solve each inequality, and then it gave me this problem jon (04:51:03:305 PM): sorry,i read it wrong,i guess all i need to do is solve it jon (04:51:24:277 PM): but how do i get the x^2 to just an x? Mod1 (04:51:30:316 PM): ah! much better. How do you know it is not an "inequality"? Mod1 (04:51:41:125 PM): (just curious) jon (04:51:59:192 PM): the square and division sign Mod1 (04:52:23:948 PM): I thought inequalities where equations with <, > and that sort of thing jon (04:52:25:927 PM): my fault,there is no division sign Mod1 (04:52:48:067 PM): equations with an = look like "equalities" dont they? jon (04:52:53:293 PM): not all my problems that are inequalities have had that jon (04:53:00:813 PM): but ur probably right jon (04:53:12:040 PM): yea Mod1 (04:53:17:451 PM): Probably not... one needs to be skeptical ;-) jon (04:53:22:604 PM): haha system (04:53:22:891 PM): Tyler entered the Algebra2 chat room. Mod1 (04:53:35:618 PM): Anyway... you said you wanted to get rid of the x^2, right? jon (04:53:51:996 PM): yea,get it to an x Mod1 (04:54:26:350 PM): if we got rid of the square (magically), you think you could solve it? jon (04:54:32:783 PM): yea Mod1 (04:55:07:658 PM): great jon (04:55:12:495 PM): it would be x=-20 Mod1 (04:55:20:651 PM): what do you think, Tyler? Mod1 (04:55:55:320 PM): we need a magic "get-rid-of-square" tool jon (04:56:02:541 PM): haha jon (04:56:04:112 PM): i know Tyler (04:56:23:175 PM): I came in late, but it looks like the solution is going to be imaginary, no? Mod1 (04:56:35:406 PM): now, when you did 5x + 100 = 0, you got rid of the 100 and of the 5 to get x = -20, how did you do that? system (04:57:07:958 PM): jon left the Algebra2 chat room. Mod1 (04:57:13:031 PM): imaginary!!! do you know what that means, Jon? Mod1 (04:57:34:595 PM): Oops! we lost jon! system (04:57:35:156 PM): jon entered the Algebra2 chat room. Mod1 (04:57:43:827 PM): Wow.. what happened? jon (04:57:48:796 PM): im sorry,i acidently got kicked Tyler (04:57:49:344 PM): Check behind the refrigerator... Mod1 (04:57:54:900 PM): how? jon (04:58:05:034 PM): i hit some button on my mouse that kicked me out Mod1 (04:58:45:317 PM): I see... very nice jon (04:59:07:245 PM): thats how i got the answer Mod1 (04:59:19:858 PM): So, let me ask you a question Mod1 (04:59:41:356 PM): why did you use -100, is that a "get-rid-of-addition" tool? jon (05:00:05:400 PM): yea Mod1 (05:00:20:569 PM): and what would dividing by 5 be, then? jon (05:00:35:404 PM): -20 Mod1 (05:00:48:457 PM): I mean, what kind of "tool" would that be call? Mod1 (05:00:57:286 PM): *called* jon (05:01:12:856 PM): get-rid-of-division tool Mod1 (05:01:22:171 PM): lol Mod1 (05:01:59:170 PM): get rid of "division"? Mod1 (05:02:16:176 PM): is 5x a division? jon (05:02:29:936 PM): so if i got the 100 on the other side,and then squared the whole thing by 2, would that get rid of the square? Mod1 (05:03:04:745 PM): well let's try it jon (05:03:09:981 PM): k Mod1 (05:03:17:187 PM): what is the square of x^2, do you know? jon (05:03:29:531 PM): x Mod1 (05:03:39:223 PM): what is the square of 5? jon (05:03:51:722 PM): 25 Mod1 (05:04:08:516 PM): yes! 5^2 = 5*5, so x^2 = ? jon (05:04:35:242 PM): x*x Mod1 (05:05:00:259 PM): right! So that didn't "get-rid-of-square" but we are getting closer Mod1 (05:05:06:133 PM): let me ask you one thing again jon (05:05:08:978 PM): yea jon (05:05:29:490 PM): so x would be the square root of x^2,correct? Mod1 (05:06:04:382 PM): you said before that dividing by 5 in our example was a way to "get-rid-of-division" but we didn't have division in the equation, we had 5x = -100, so what is that "tool" called? Mod1 (05:07:04:564 PM): Am I confusin you with this "get-rid-of" business? jon (05:07:05:979 PM): im not shure jon (05:07:12:064 PM): yea lol jon (05:07:15:217 PM): sure* Mod1 (05:07:30:804 PM): I was just pointing out that with division you "get rid" of multiplication jon (05:07:39:408 PM): oh alright Mod1 (05:07:51:477 PM): so let's try to "get rid of squares" as you wanted jon (05:07:59:084 PM): ok Mod1 (05:08:15:264 PM): I will put a value of x in the canvas and you put the sqaure, o.k? jon (05:08:23:615 PM): ok Mod1 (05:09:12:911 PM): *I know it is hard to draw with a potato!* jon (05:09:18:587 PM): lol Mod1 (05:09:21:302 PM): very good jon (05:09:22:429 PM): yea Mod1 (05:09:54:974 PM): so, you already know that if you hava additions in an equation (like +100) then you subtract jon (05:10:07:001 PM): yes Mod1 (05:10:16:787 PM): and if x is multiplied by a factor, you divide, like in 5x jon (05:10:23:821 PM): yes Mod1 (05:10:33:631 PM): so... Mod1 (05:11:02:293 PM): if we had an equation that said x^2 = 25, using the table below you could say what x is, right? jon (05:11:19:021 PM): yes jon (05:11:26:265 PM): 5 Mod1 (05:11:43:452 PM): great! so we found our "get-rid-of-square" tool, right? jon (05:11:48:389 PM): yes Mod1 (05:11:55:720 PM): what should we call it? jon (05:12:11:633 PM): get-rid-of-squares jon (05:12:14:621 PM): tool Mod1 (05:12:34:022 PM): we should call it "jon's get-rid-of-square" tool! ;-) jon (05:12:40:629 PM): ok deal jon (05:12:43:057 PM): haha Mod1 (05:12:47:198 PM): well, in reality it already has a mathematical name, unfortunately! Mod1 (05:13:16:574 PM): how sad and boring... it is called "squared root" and it has a funny symbol, have you seen it? jon (05:13:32:313 PM): yea Mod1 (05:13:50:651 PM): can you draw it on our equation x^2 = 25 Mod1 (05:14:22:054 PM): yeah! that's it Mod1 (05:14:33:291 PM): now, use it on our equation Mod1 (05:14:55:615 PM): remember, like when you used the other "tools" you have to do it in both sides jon (05:15:30:735 PM): sorry,its kind of messy Mod1 (05:15:54:741 PM): dont' worry about that. jon (05:16:27:862 PM): would that be it? Mod1 (05:16:34:916 PM): wow? what is 10i? jon (05:16:50:618 PM): i stands for an imaginary number Mod1 (05:17:06:772 PM): an imaginary number? I thought all numbers were imaginary after all? Mod1 (05:17:52:935 PM): jk jon (05:18:01:732 PM): i stands for -1 which is a imaginary number supposiblyin this case Mod1 (05:18:03:686 PM): something looks strange on the left side, jon Mod1 (05:18:16:954 PM): doesn't it? jon (05:18:26:630 PM): yea jon (05:18:56:842 PM): i just dont know what it is lol Mod1 (05:18:57:346 PM): what is it? Mod1 (05:19:24:052 PM): let's just play with that part... jon (05:19:28:693 PM): ok Mod1 (05:19:44:213 PM): we know that the square root of x^2 is x jon (05:19:49:916 PM): yes Mod1 (05:20:34:638 PM): but now, we have 5x^2 and you think that the square root of that is x(sqrt(5x)) jon (05:21:36:535 PM): so would it just be x(sqrt(5) instead? jon (05:21:48:795 PM): because x^2 is x? Mod1 (05:21:52:848 PM): why the sudden change? ;-) Mod1 (05:22:02:459 PM): right! Mod1 (05:22:26:202 PM): let's do it with numbers just to test it jon (05:22:36:056 PM): so the answer to my problem is x(sqrt(5)= 10i? jon (05:22:37:234 PM): ok Mod1 (05:23:31:512 PM): what would that blue equation be ?Mod1 (05:24:26:042 PM): what do you think, jon? Mod1 (05:24:59:390 PM): do you have a calculator handy? jon (05:25:07:959 PM): yea Mod1 (05:25:28:565 PM): try it out... Mod1 (05:25:34:320 PM): why did you change your mind? Mod1 (05:27:13:108 PM): did it work on the calculator? jon (05:27:14:542 PM): 2^2 = 4, 5*4 = 20 5*4= 20 sqrt of 4=2,therefore 2(sqrt(5) is correct Mod1 (05:27:48:043 PM): but you first guessed the other one... is it still not clear? jon (05:28:11:235 PM): i get it now Mod1 (05:28:30:565 PM): let me clear the canvas just to do a few more tests, and then we finalize your answer, ok? jon (05:28:42:589 PM): i accidentl did 20 divided by 2 at first Mod1 (05:29:37:257 PM): *that is sqrt (8 * 3^2 ) = ? Mod1 (05:30:44:902 PM): jon? Mod1 (05:31:18:938 PM): r u still there? jon (05:31:23:320 PM): yea jon (05:31:28:684 PM): im trying to figure it out Mod1 (05:31:34:657 PM): ah! did you figure that problem? Mod1 (05:31:48:081 PM): *you are not doing it in the calculator, are you?* jon (05:31:53:809 PM): yea Mod1 (05:32:18:188 PM): Oh! I see! But we can do it just by looking at it. Can't we? jon (05:32:32:851 PM): 72= 9*8 3(sqrt(8) is correct Mod1 (05:32:47:491 PM): very good! jon (05:32:50:695 PM): no its not jon (05:32:54:566 PM): it is? jon (05:33:04:018 PM): im good haha Mod1 (05:33:11:254 PM): yes! do you see the pattern? jon (05:33:31:092 PM): yea Mod1 (05:33:56:685 PM): so what about this one: Mod1 (05:34:55:862 PM): sqrt ( A * B^2 ) = ? jon (05:34:57:760 PM): b(sqrt(a) Mod1 (05:35:04:285 PM): sure! jon (05:35:18:010 PM): i have another problem if u dont mind Mod1 (05:35:43:752 PM): let me wrapp it up and then we do the other one... jon (05:35:49:276 PM): k Mod1 (05:36:14:585 PM): what about sqrt ( a + b ^2 ) = ?Mod1 (05:36:33:941 PM): oops. that was sqrt (a + b^2) Mod1 (05:37:04:267 PM): =? jon (05:37:32:990 PM): would it be b(sqrt(a)? Mod1 (05:38:12:351 PM): gotcha! you can't do that with addition, jon! only with factors jon (05:38:19:362 PM): oh ok Mod1 (05:38:28:066 PM): but I don't want to confuse you too much, I just wanted you to be aware of it jon (05:38:36:278 PM): alrighty Mod1 (05:38:44:466 PM): so, last step for your problem... jon (05:40:20:618 PM): correct? Mod1 (05:41:01:221 PM): great! or sqrt(5) * x = 10i Mod1 (05:41:06:233 PM): but... Mod1 (05:41:20:498 PM): we might want the variable x to be alone as in x = ... Mod1 (05:41:23:992 PM): how do we do that? jon (05:41:59:107 PM): multiply each side by sqrt of 5 Mod1 (05:42:44:877 PM): brilliant! I thought that you would use the "get-rid-of-squareroot" tool but you used the "get-rid-of-factor" tool! Excellent! Mod1 (05:42:56:022 PM): except... Mod1 (05:43:09:291 PM): why would we multiply? Mod1 (05:43:39:938 PM): shouldn't we... Mod1 (05:44:11:537 PM): *do something else* Mod1 (05:44:45:049 PM): jon? jon (05:44:56:951 PM): isnt it if u multiply a square root by itself u will get the factor inside the root symbol? Mod1 (05:45:43:072 PM): true.. if you multiply sqrt(5) * sqrt(5) we get = 5 Mod1 (05:45:59:030 PM): but we want the x alone jon (05:46:05:815 PM): yea Mod1 (05:46:26:924 PM): what would you do, if you had 5x = 10 and you wanted to "get-rid-of" the 5? jon (05:46:39:587 PM): divide by 5 Mod1 (05:47:02:722 PM): ah! so what can we do now that we have sqrt(5) x = 10i ? jon (05:47:47:644 PM): divide by the sqrt of 5 Mod1 (05:48:49:922 PM): yes.. sqrt(5) is just another number... you can get the actual value from your calculator but it doesn't matter what it is jon (05:49:09:043 PM): ok Mod1 (05:49:15:811 PM): so.... x = ? jon (05:49:31:429 PM): 101 over sqrt of 5 jon (05:49:41:738 PM): but hteres a problem.... jon (05:49:57:551 PM): theres* jon (05:50:32:428 PM): u cant have a square root in the denominator place Mod1 (05:50:43:647 PM): why not? jon (05:51:23:768 PM): the rule is that u cant have a square root sign in the denominator spot,atleast thats what my teacher told me Mod1 (05:51:53:009 PM): really? Mod1 (05:52:02:731 PM): what about this: jon (05:52:05:105 PM): thats what im thinking Mod1 (05:52:27:936 PM): x = 10 / sqrt (4) Mod1 (05:52:32:613 PM): do you see a problem with that? jon (05:53:19:907 PM): how did u get 10/sqrt (4)? Mod1 (05:53:54:494 PM): that was just another example... not related to your equation jon (05:53:58:781 PM): wouldnt it be x= 10i(sqrt(5)/25? Mod1 (05:54:09:178 PM): can you see what x would be in that case? jon (05:54:10:992 PM): oh ok system (05:54:26:690 PM): jerzeygirl714 entered the Algebra2 chat room. jon (05:54:34:342 PM): it would be 5/8 Mod1 (05:55:18:942 PM): it would be 10 / 2, right? system (05:55:38:830 PM): jerzeygirl714 left the Algebra2 chat room. system (05:55:48:099 PM): RoMol9 entered the Algebra2 chat room. jon (05:55:48:100 PM): sorry,i thought it read 4squared Mod1 (05:56:34:636 PM): Did you see why it was 10 / 2, jon? RoMol9 (05:56:49:968 PM): Hi can you show me to add and subtract time cause i dont know and i have my TAKS test the 5th Mod1 (05:56:50:532 PM): Jon, would you like to help me help RoMo19? Mod1 (05:57:27:918 PM): Sure, Ro! Let me see if we are done with jon RoMol9 (05:57:41:209 PM): ok Mod1 (05:57:41:706 PM): and we will try to help you out RoMol9 (05:57:58:399 PM): ok Mod1 (05:58:02:246 PM): jon... are you o.k. with your answer? jon (05:58:24:165 PM): i understand now Mod1 (05:58:33:815 PM): in the meantime, let me give you some additions to do, Ro RoMol9 (05:58:48:391 PM): ok Mod1 (05:59:07:497 PM): go ahead, Ro Mod1 (05:59:22:854 PM): Jon, there was one thing I wanted to mention to finish your problem... jon (05:59:27:737 PM): ok Mod1 (05:59:54:892 PM): First, check with your teacher about the square-in-the-denominator rule, ok? jon (06:00:08:913 PM): ok,i will Mod1 (06:00:11:208 PM): Wow, you are good, Ro! RoMol9 (06:00:40:091 PM): well i am in the 5th grade jon (06:01:02:268 PM): i have to head out alright Mod1 Mod1 (06:01:03:489 PM): try the subtractions, Ro Mod1 (06:01:10:594 PM): And jon, one more thing... jon (06:01:17:256 PM): yes Mod1 (06:01:46:446 PM): what number is the square root of 4? jon (06:01:51:182 PM): 2 Mod1 (06:02:03:057 PM): why? jon (06:02:12:348 PM): because 2*2= 4 Mod1 (06:02:32:088 PM): Brilliant, Ro! Give me an example of an addition or subtraction that you are having problems with! jon (06:02:52:130 PM): thank you so much for the help mod Mod1 (06:03:10:360 PM): jo, is there any other number that multiplied by itself = 4? jon (06:03:30:623 PM): nope Mod1 (06:03:42:454 PM): sure about it, jon? jon (06:04:01:177 PM): the only multiples are 2,2 and 4,1 Mod1 (06:04:25:169 PM): what if you could use negative numbers, jon? jon (06:04:39:510 PM): -2*-2 Mod1 (06:04:49:065 PM): Interesting, Ro Mod1 (06:04:57:431 PM): what do those numbers mean? Mod1 (06:05:21:655 PM): Ah!!! See, jon! we found another answer to sqrt(4)! Scary! RoMol9 (06:05:41:982 PM): 3hrs.21min. RoMol9 (06:06:04:423 PM): 3hrs.21min-43min system (06:06:23:395 PM): jon left the Algebra2 chat room. Mod1 (06:06:27:327 PM): Ah! You are adding time! Interesting! RoMol9 (06:06:48:501 PM): yup Mod1 (06:06:51:034 PM): so how do you do that? RoMol9 (06:08:04:909 PM): I don't know not one clue Mod1 (06:08:07:142 PM): Ro? RoMol9 (06:08:27:670 PM): Uh huh? Mod1 (06:08:29:023 PM): still there? Mod1 (06:08:40:719 PM): oh, great. lets see Mod1 (06:09:00:722 PM): do you know how many minutes are there in an hour? RoMol9 (06:09:01:069 PM): yeah RoMol9 (06:09:27:406 PM): 60 Mod1 (06:09:36:543 PM): how many? Mod1 (06:09:54:214 PM): *sorry* 60 yes! RoMol9 (06:09:56:421 PM): 60 min. RoMol9 (06:10:08:013 PM): ok... Mod1 (06:10:13:419 PM): so if you add 20 minutes and 15 minutes, how much you get? RoMol9 (06:10:49:198 PM): 35 min? RoMol9 (06:11:29:287 PM): is it right Mod1 (06:11:36:961 PM): great, and if I told you that I'll give you 45 minutes to play one video game and another 30 minutes to play tomorrow in total how many minutes can you play? RoMol9 (06:12:45:388 PM): 75 min./ 1hr. 15 min.Mod1 (06:12:55:560 PM): brilliant! Mod1 (06:13:11:384 PM): how did you figure that it was 1hr and 15 minutes? RoMol9 (06:13:20:563 PM): Thanks I subtracted 60 min. from 75 min. Mod1 (06:13:58:724 PM): And if I gave you 215 minutes total? how many hours will you have to play? Mod1 (06:15:12:031 PM): *Ro is thinking* isn't he/she? RoMol9 (06:15:26:636 PM): 3hrs.and 35min.? Mod1 (06:15:35:584 PM): How did you figure that out? RoMol9 (06:16:03:622 PM): is it right Mod1 (06:16:29:329 PM): tell me how you did it and then I will now if it is right ;-) RoMol9 (06:17:05:517 PM): well i kept on subtracting 60 from the answer and then counted all the 60 plus the 35 min. extra RoMol9 (06:18:17:704 PM): did I do it right? RoMol9 (06:18:58:977 PM): r u there? RoMol9 (06:19:51:596 PM): Hello???? RoMol9 (06:20:02:096 PM): MOd? Mod1 (06:20:12:689 PM): sorry.. my machine got hanged Mod1 (06:20:15:992 PM): yes I am here RoMol9 (06:20:41:120 PM): ok so did i do it right? Mod1 (06:20:49:972 PM): that was a very clever way of doing the problem, Ro! Mod1 (06:21:03:433 PM): and the answer was correct, of course RoMol9 (06:21:06:953 PM): ok... RoMol9 (06:21:16:538 PM): yeah! RoMol9 (06:21:51:484 PM): now but I still do have trouble is that how you work out every problem Mod1 (06:22:10:113 PM): so If i discovered that you didn't eat your spinach at lunch and decided that you will play less time, one hour less exactly, how much you will have left to play? Mod1 (06:22:43:515 PM): give me a problem that you have trouble with, Ro Mod1 (06:22:54:552 PM): *ignore my other question* RoMol9 (06:24:55:122 PM): ok well I don't really know any... but i also have trouble adding time and well I'd like to learn Mod1 (06:25:40:949 PM): It doesn't seem to me that you have any trouble with time... you did remarkbly well RoMol9 (06:26:06:088 PM): yeah but you should see me at school Mod1 (06:26:21:236 PM): very funny! What happened at school? RoMol9 (06:26:27:536 PM): I cant figure things out Mod1 (06:26:46:332 PM): sounds surprising... you've done so well here Mod1 (06:26:51:565 PM): why would it be different? RoMol9 (06:27:24:891 PM): nothing well my science grades started getting lower since my other teacher stopped teaching me RoMol9 (06:28:04:205 PM): And I'm a strait A student I've been on the honor roll my whole life and now i get 80's Mod1 (06:28:10:664 PM): stopped teaching you? wow! Mod1 (06:28:15:244 PM): let me ask you a question, Ro... Mod1 (06:28:24:342 PM): maybe we did too simple problems RoMol9 (06:28:27:880 PM): in math and Science RoMol9 (06:28:33:509 PM): ok RoMol9 (06:28:54:237 PM): maybe Mod1 (06:29:29:950 PM): do you get problems like the one on the canvas RoMol9 (06:29:59:904 PM): I don't know what do you mean RoMol9 (06:30:21:823 PM): the addition & subtraction? Mod1 (06:30:31:398 PM): I mean that we are adding and subtracting time but not doing complicated problems like the one I just put on the canvas RoMol9 (06:30:33:096 PM): if that's what you mean yes Mod1 (06:30:58:994 PM): do you think your teacher will give you a problem like that? RoMol9 (06:31:11:010 PM): yeah RoMol9 (06:31:29:868 PM): like what there's no problem on the canva Mod1 (06:31:38:670 PM): I see... and how would you go about solving that problem? Mod1 (06:31:55:520 PM): don't do it on a piece of paper... try to do it here with me RoMol9 (06:32:31:276 PM): What r u talking about? RoMol9 (06:32:35:593 PM): what problem Mod1 (06:32:58:064 PM): the one on the canvas... can you see it? RoMol9 (06:33:09:485 PM): nope!~ Mod1 (06:33:36:471 PM): let me try to draw it again... RoMol9 (06:33:48:199 PM): ok Mod1 (06:34:53:569 PM): do you see it now? Mod1 (06:35:14:806 PM): 3h 27m 14s - 1h 43m 50s = ? RoMol9 (06:35:21:507 PM): nope still cant see it Mod1 (06:35:38:324 PM): very strange... can you draw something on the canvas, please RoMol9 (06:35:45:359 PM): can i work it on paper? RoMol9 (06:35:54:125 PM): ok Mod1 (06:36:13:889 PM): wow... I can see what you draw but you can't see what I draw Mod1 (06:36:17:015 PM): strange... Mod1 (06:36:22:518 PM): go ahead and do it on paper RoMol9 (06:36:34:518 PM): I know freaky Mod1 (06:36:39:030 PM): but tell me the steps that you take one by one here RoMol9 (06:36:50:863 PM): so can i work the problem out on paper Mod1 (06:37:46:173 PM): sure... where do you start? Mod1 (06:38:00:543 PM): *btw, you have very good spelling!* RoMol9 (06:38:54:912 PM): 3hrs. 10min. 64 sec. RoMol9 (06:39:11:791 PM): is it the right answer RoMol9 (06:39:11:791 PM): thanks RoMol9 (06:39:28:656 PM): I was a strait A student RoMol9 (06:39:44:762 PM): BRB hold on Mod1 (06:41:15:295 PM): sure... Mod1 (06:41:32:305 PM): 3hrs 10min 64 sec is not correct, Ro RoMol9 (06:42:30:632 PM): ooh so how can i get the answer Mod1 (06:42:54:175 PM): tell me how you got that answer? RoMol9 (06:43:34:141 PM): i subtracted evrything Mod1 (06:43:56:310 PM): so, lets start with the seconds RoMol9 (06:44:09:349 PM): but i just relized i messed up the subtraction Mod1 (06:44:18:691 PM): try again, then RoMol9 (06:44:28:238 PM): can I do it over Mod1 (06:44:31:002 PM): just the seconds, how do you do it? Mod1 (06:44:48:476 PM): 3h 27m 14s - 1h 43m 50s = ? RoMol9 (06:45:20:732 PM): 14-50 RoMol9 (06:45:20:732 PM): hold on RoMol9 (06:46:48:605 PM): I give up I cant get the answer Mod1 (06:47:01:936 PM): Ro, I am going to have to go in a couple of minutes, unfortunately Mod1 (06:47:14:294 PM): so let me explain it to you, ok? RoMol9 (06:47:29:258 PM): can you ok Mod1 (06:48:24:316 PM): Sure. If you have 40 seconds and you substract 10 seconds you get 30 seconds and that is easy to do because the first number (40) is bigger than the second (10)RoMol9 (06:48:50:072 PM): yes Mod1 (06:48:51:491 PM): but in this case, we have 14 seconds and we want to subtract 50 seconds and that is not possible directly, correct? RoMol9 (06:49:27:342 PM): yeah Mod1 (06:49:35:898 PM): but I am sure that you now about "borrowing" in subtraction, right? RoMol9 (06:49:55:144 PM): of course RoMol9 (06:50:31:949 PM): but can you borrow from min. or hrs. Mod1 (06:50:42:117 PM): we can borrow one minute which is equal to 60 seconds so that instead of 14 seconds we have 60 plus 14 seconds (74) and then we will be able to subtract from 74 the 50 secondsMod1 (06:50:45:989 PM): to get.. Mod1 (06:51:23:063 PM): in other words 3hr 27 min 14 sec is the same as 3hr 26min 74 sec, right? RoMol9 (06:51:37:284 PM): ok I get you so it would be 74 -50 RoMol9 (06:51:53:308 PM): yup Mod1 (06:51:54:556 PM): yes! that is how you "borrow" with hours, minutes and seconds Mod1 (06:52:10:264 PM): now when we get to the minutes we have the same problem RoMol9 (06:52:28:162 PM): ok cool you'r a really good teacher Mod1 (06:52:31:357 PM): we have now 26 minutes and we want to subtract 43 minutes which is greater... how could we do that? RoMol9 (06:53:03:024 PM): we borrow from hrs. Mod1 (06:53:25:707 PM): brilliant! So instead of 3hr 26 mins what do we use? Mod1 (06:53:42:426 PM): remember 1 hr is 60 minutes RoMol9 (06:54:12:345 PM): 2hrs and 86 min I'm pretty sure I got them wrong though Mod1 (06:54:28:538 PM): 2hrs and 86 mins is perfect. RoMol9 (06:54:46:571 PM): OMG RoMol9 (06:54:57:794 PM): I know how to Borrow Mod1 (06:55:01:139 PM): We had 3 hrs and 26 minutes which is the same as 2hrs and 86 minutes! RoMol9 (06:55:10:272 PM): cool RoMol9 (06:55:27:450 PM): u'r a really good teacher Mod1 (06:55:43:135 PM): we subtract the 43 mins from the 86 mins to get 43 and then we do the hours that are really easy ... 2hrs - 1hrs? RoMol9 (06:56:05:374 PM): 1hr. RoMol9 (06:56:13:889 PM): hold on? Mod1 (06:56:39:794 PM): Yes! So the answer is...Mod1 (06:57:20:063 PM): 1hr 43min and 24 seconds Mod1 (06:57:40:356 PM): And we got it almost excately at 7:00 pm the time that we close this chat, Ro! ;-) Mod1 (06:58:12:005 PM): Do you think you know how to borrow time to add and subtract? RoMol9 (06:58:24:376 PM): is it 2hrs and 26 min. and 25 sec I kind of know i got it wrong RoMol9 (06:58:48:100 PM): I'm kinda getting there RoMol9 (06:59:04:966 PM): so did i get it wrong or right RoMol9 (06:59:39:241 PM): Hello? RoMol9 (07:00:06:851 PM): Mod? RoMol9 (07:00:36:585 PM): R u not there? system (07:00:54:937 PM): RoMol9 left the Algebra2 chat room. Mod1 (07:02:28:400 PM): yes you did. sorry come back next Thursday. Thanks. system (07:02:33:583 PM): Mod1 left the Algebra2 chat room. system (07:24:56:585 PM): Tyler left the Algebra2 chat room.