system (12:25:03:217 PM): Mod1 has joined Babylon. Mod1 (12:25:18:111 PM): Welcome Dr. Math! Mod1 (12:26:21:045 PM): Testing server.... system (12:26:31:310 PM): Mod1 left the Main chat room. system (12:27:22:884 PM): Mod1 has joined Babylon. system (02:57:47:049 PM): Ian has joined Babylon. system (03:31:36:350 PM): Ian left the Main chat room. system (03:49:13:118 PM): Mod2 has joined Babylon. system (03:49:22:004 PM): Mod2 left the Main chat room. system (03:49:55:677 PM): Ian has joined Babylon. system (03:54:13:393 PM): mijitpride has joined Babylon. system (03:54:17:421 PM): hayley has joined Babylon. mijitpride (03:54:37:847 PM): watsup ian Ian (03:54:42:777 PM): Hi mijit, hayley. Welcome! Ian (03:54:56:241 PM): Nothing much is up yet. We just got started. Mod1 (03:55:00:966 PM): Hi, mijit! How punctual! hayley (03:55:03:250 PM): hello Mod1 (03:55:17:284 PM): Hi, hayley! Welcome. hayley (03:55:32:791 PM): wot do we do on this exactly Mod1 (03:55:56:797 PM): Well... if you have a math question we can try to solve it together hayley (03:56:16:814 PM): how do u do algabra Ian (03:56:23:345 PM): That's a big topic! hayley (03:56:29:546 PM): i know Ian (03:56:34:992 PM): It's kind of like asking "How do you write a short story." :^D hayley (03:56:43:688 PM): it isnt Ian (03:56:50:217 PM): Is there a particular kind of algebra problem you're having trouble with? hayley (03:57:35:101 PM): well just workin out if the answer is 1000 and p is 150 bigger wot is q mijitpride (03:58:09:438 PM): so ... Ian (03:58:10:710 PM): So there's some kind of equation you're starting with? hayley (03:58:43:257 PM): no not really hayley (03:59:22:641 PM): how do u work it out mijitpride (03:59:45:886 PM): start by interpreting it into an equation Ian (04:00:51:738 PM): Do you mean that p is 150 more than q, and the sum of p and q is 1000? system (04:00:52:960 PM): racshattuck has joined Babylon. hayley (04:01:22:844 PM): yes it all equals 1000 Ian (04:02:02:556 PM): So you have two facts: p is 150 more than q; and p+q = 1000. Right? hayley (04:02:10:468 PM): wot year are u in ian racshattuck (04:02:26:302 PM): i need help in math i got a C on my report card to day it is hard racshattuck (04:02:42:185 PM): PLEASE HELP ME Mod1 (04:02:54:556 PM): Wow, perhaps we can all help racshat! hayley (04:03:00:377 PM): ok wot did u get stuck on mijitpride (04:03:03:230 PM): give us something you need help with hayley (04:04:01:794 PM): so wot u need help with Ian (04:04:13:275 PM): Racshat, can you give us an example of a problem that you would have trouble with, say on a test? system (04:04:16:592 PM): omega has joined Babylon. Ian (04:04:22:313 PM): Hi Omega. hayley (04:04:31:958 PM): hi omega racshattuck (04:04:43:792 PM): well i am in 5th grade and i cant get pie omega (04:04:53:127 PM): hi mijitpride (04:05:00:719 PM): do you mean pi ... racshattuck (04:05:21:592 PM): yeah soory Ian (04:05:37:887 PM): What have you learned about pi so far? racshattuck (04:06:17:033 PM): that there is curufrance,radis,and diameter Ian (04:06:32:282 PM): Okay. Do you have a good idea of what those words mean? racshattuck (04:06:50:680 PM): no Ian (04:07:03:359 PM): Do you know what 'perimeter' means? racshattuck (04:07:27:450 PM): yes hayley (04:07:39:763 PM): i dont know wot u are doin Ian (04:07:44:828 PM): The circumference of a circle is the same as the perimeter of the circle. Ian (04:07:50:654 PM): It's just a different word for the same idea. Mod1 (04:07:51:074 PM): Guys... I know it is fun to draw on the whiteboard but since it is shared for everybody it is a bit confusing if we all use it at the same time... system (04:08:17:047 PM): hayley left the Main chat room. system (04:08:27:427 PM): hayley entered the Main chat room. racshattuck (04:08:34:344 PM): ok i see the circle Mod1 (04:09:04:892 PM): let's have mijit draw for now untill racshat understands pi, and then we can try someone else's question, ok? racshattuck (04:10:21:103 PM): did i get it right mijitpride (04:10:28:342 PM): yes .. you did mijitpride (04:10:47:102 PM): now try this racshattuck (04:10:47:403 PM): yeah system (04:10:47:701 PM): hayley left the Main chat room. racshattuck (04:11:53:276 PM): i am leaving racshattuck (04:11:58:960 PM): bye system (04:12:23:547 PM): racshattuck left the Main chat room. system (04:12:41:160 PM): Ian left the Main chat room. system (04:12:55:300 PM): mijitpride left the Main chat room. system (04:13:08:983 PM): omega left the Main chat room. system (04:21:26:627 PM): racshattuck entered the Main chat room. system (04:21:32:458 PM): racshattuck left the Main chat room. Mod1 (04:22:39:911 PM): Hey, racshat? Mod1 (04:37:48:265 PM): Welcome to Dr. Math Chat system (04:38:39:966 PM): Mental_Siege has joined Babylon. system (04:39:55:715 PM): Ean has joined Babylon. Mental_Siege (04:39:58:011 PM): Yeah. I was just trying to factor 9a^2-4b^2-12b-9. A CAS tells me it's (3a+2b+3)*(3a-2b-3), but I'm trying to do it by hand, and I can't quite see how. Mod1 (04:40:45:335 PM): Hi, Ean! Would you help me with help Mental? Mod1 (04:40:55:444 PM): Lets see... Ean (04:41:08:099 PM): Sure. Mod1 (04:41:10:958 PM): What is "a CAS"? Mental_Siege (04:41:46:792 PM): I know taht 9a^2-4b^2 is (3a+2b)*(3a-2b). .. difference of squares. Looks like I should be able to get it from there... but... well, not sure how! Mental_Siege (04:41:56:733 PM): Computer algebra system. In this case, just a TI-89. =) Mod1 (04:42:18:465 PM): I see... Mod1 (04:42:27:157 PM): lol Ean (04:42:41:164 PM): I guess the first thing I notice is that you've got (3a)^2 + stuff - 3^2, which looks like a difference of squares. Mod1 (04:42:45:929 PM): Let me put your equation in the shared whiteboard... just a sec Mental_Siege (04:43:31:775 PM): I've never been here. Pretty neat. Mod1 (04:43:54:931 PM): Glad you like it, MS! Can you repeat what you said, Ean? Ean (04:44:08:707 PM): Andyou have another difference of squares: (3a)^2 - (2b)^2. Mod1 (04:44:55:402 PM): I see, Ean, can you draw a red line under all the "squares" you found in the equation? Mod1 (04:45:43:559 PM): pretty, cool Mental_Siege (04:46:07:166 PM): How can I draw on the whiteboard?... can't quite figure out how. Mod1 (04:47:05:331 PM): The whiteboard is shared by all, so be careful. Just use the "Drawing Controls" freehand, line, etc and drag your mouse over the white canvas. Mod1 (04:47:47:229 PM): So... any ideas how do we factor those three "squares" and the other "stuff" that Ean found? Mental_Siege (04:48:43:641 PM): Hmm. Let's see. I suppose 9 is also a square. ::ponders.:: Mental_Siege (04:51:44:461 PM): The best I've been able to do after that, using using kind of ad-hoc reasoning... 9 looks like a square, and I can see that if I put +3 and -3 into those other two factors, a lot of stuff will cancel. But that's working backwards when I know the answer... not sure I would've seen it just working forward. Ean (04:52:14:408 PM): Yeah, it's difficult to see a path from the unfactored form to the factored one. Ean (04:53:57:982 PM): I suppose someone who made up the problem started with (a+b+c)(a-b-c) to see what kind of pattern would result. Mental_Siege (04:54:08:799 PM): ::grins.:: Probably so. system (04:54:10:582 PM): mijitpride has joined Babylon. system (04:54:22:144 PM): mijitpride left the Main chat room. Mod1 (04:54:22:784 PM): let's see... Mod1 (04:55:35:746 PM): what does (a + b + c)(a + b + c) leads to? Mental_Siege (04:56:42:417 PM): (a + b + c) * (a - b - c) = a^2 - b^2 - 2*b*c - c^2 ... looks a little like the law of cosines. Ean (04:57:58:669 PM): It does, doesn't it? Mod1 (04:58:35:412 PM): Right, so how many squares do we see in that result? Mental_Siege (04:58:59:233 PM): Hm. Three. Mod1 (04:59:25:324 PM): Sounds familiar? Mental_Siege (05:00:33:841 PM): ..hm. No, not really.... I think... I'll just hang my head in shame and move on to the next problem. Heh. Mental_Siege (05:00:41:254 PM): Thanks for the help, though! =) Mod1 (05:01:08:728 PM): Noo wait Mod1 (05:01:32:148 PM): We almost have it here! Mod1 (05:01:53:554 PM): you guys have done 90% of the work already Mod1 (05:02:30:724 PM): Let me draw what you found but use x y z instead of a b c so that we don't get confused, ok? Mental_Siege (05:02:41:049 PM): ok. Mod1 (05:05:13:328 PM): Does that make sense? Mental_Siege (05:05:55:733 PM): equals ... (x - y - z) * (x + y + z), right? Mod1 (05:06:17:589 PM): right! Mod1 (05:07:00:883 PM): So, what would x be? Mod1 (05:07:39:926 PM): MS? Mental_Siege (05:07:41:601 PM): If I figured on knowing this formula.... looks pretty easy to remember, especially if I keep the law of cosines in mind... x = 3a, y = 2b, z = 3 , i think Mod1 (05:08:12:132 PM): what do you think, Ean? Does that answer make sense to you? Ean (05:08:33:660 PM): Yeah. But I still wonder if there's a way to see it going forwards, without already knowing where it came from. Ean (05:09:08:807 PM): It kind of reminds me of that famous problem, where some brothers are trying to divide up the sheep left to them by their father... Mental_Siege (05:09:20:144 PM): Well... everything else in the book is "memorize this factoring fomula." I wonder if this would be an useful factoring fomula to memorize. Ean (05:09:27:781 PM): and a wise man helps them by adding in one of his own sheep, which makes all the fractions work out, then takes his own sheep back at the end... Ean (05:09:49:056 PM): I do believe this is the first time I've ever seen this one. Mod1 (05:10:02:894 PM): very interesting... Mod1 (05:10:51:350 PM): now, I think that you found the first step "forwards" when you noticed that there were 3 "squares" in the original expression, right? Ean (05:10:54:426 PM): But there's a lot of stuff I haven't seen! Mod1 (05:11:27:991 PM): lol, of course! Ean (05:11:30:369 PM): Hmmmm. Ean (05:12:03:993 PM): (a+b+c)(a-b-c) = (a+(b+c))(a-(b+c)), right? Mental_Siege (05:12:06:323 PM): Something like that, yeah. (3a + 2b) * (3a - 2b) -12b -9.... well, doesn't really look completely factored, with that additional square sitting out there, and a the minus sign. Mental_Siege (05:12:41:641 PM): Hey, yeah. system (05:12:51:903 PM): gram1942 has joined Babylon. Mod1 (05:13:01:944 PM): very clever! Mod1 (05:13:40:684 PM): hi, gram1942... be careful with the whiteboard because it is shared by everyone! Mod1 (05:14:31:387 PM): let me just make sure that MS understood our last problem, did you MS? Mental_Siege (05:14:52:137 PM): Mod1, I think so. That last thing Ean came up with... pretty neat. Mod1 (05:15:22:922 PM): Yeah, I agree. Very clever! Mod1 (05:15:55:584 PM): Ean, did you have a question? Maybe we can tackle your question as a group, too and then work on gram1942's question, ok? Ean (05:16:59:529 PM): I was hoping someone could explain substitution to me. Mod1 (05:17:05:859 PM): or we can work on gram's question... what would you preffer? Mod1 (05:17:25:356 PM): Substitution! Do you have a particular problem in mind? Ean (05:18:12:674 PM): Well, like if you have 2x + 3y = 9 and 4x - 3y = -2. system (05:18:39:576 PM): gram1942 left the Main chat room. Mod1 (05:19:09:971 PM): let me put your equations on the board... Mod1 (05:20:16:252 PM): 2 equations, 2 variables... what do we do? Ean (05:20:56:155 PM): Well, the thing is, I know you can solve for one, like y=(9-2x)/3. And then you put that in the other equation. But I don't get *why* it works. Mod1 (05:22:38:813 PM): I see... what do you think, MS? Mental_Siege (05:22:56:166 PM): Hmmm. Well, I don't know if it's insightful or not. But I tend to think of each equation as designating a set of constraints on the numbers. When you solve for one and plug it into the other one, you're applying both sets of constraints simultaneously, solving the equation... Mental_Siege (05:23:17:960 PM): Could 2x + 3y = 9 be .. graphed? Mental_Siege (05:24:00:582 PM): my math is a little rusty. dug out the old algebra book, brushing up. =) Mod1 (05:24:18:914 PM): What do you think, Ean? system (05:24:23:574 PM): sweetpeas has joined Babylon. Mod1 (05:24:51:803 PM): Hi, sp. Welcome. We are trying to help Ean understand substitution Ean (05:25:22:097 PM): I don't get the plugging in part. I know you can take a number and substitute it for a variable. But I don't see how you can just grab part of another equation and stick it in there. sweetpeas (05:25:39:334 PM): hi, I have a math problem can anyone help me after ean? Ean (05:26:53:273 PM): We can do sweet's problem if you want. It's okay. Mental_Siege (05:27:57:857 PM): If you solve for y, y is a number... that's still true, even though you haven't yet determined what number it is. Mod1 (05:28:09:316 PM): Sure, sp! Ean and MS are very good at helping people with math questions... lets finish up with Ean because we are very close Mental_Siege (05:28:20:662 PM): You can solve it for a number. It must've been a number all along. ;) system (05:28:25:858 PM): swcwgrl has joined Babylon. Ean (05:29:17:975 PM): It's a lot of numbers, right? y = (9-2x)/3 is a lot of different numbers, depending on what x is. swcwgrl (05:29:26:467 PM): hi, maybe someone can help us out please? We are trying to find out what a square product is. Mod1 (05:29:38:024 PM): So Ean asks, why can you plug one equation into another... anybody has any ideas for him? Mental_Siege (05:29:46:573 PM): Right. A whole line. system (05:29:47:120 PM): p00F has joined Babylon. system (05:29:55:582 PM): sweetpeas left the Main chat room. p00F (05:30:12:973 PM): hi Ean (05:30:21:368 PM): Do you have some context for the 'square product' question? p00F (05:30:28:505 PM): ? p00F (05:30:29:957 PM): huh p00F (05:30:35:125 PM): i need help Mod1 (05:30:39:350 PM): Sure, swcwgrl... we can help you in a second... let us finish with Ean's question and we will be work on yours Mental_Siege (05:30:43:584 PM): I think she disconnected. Mental_Siege (05:30:55:990 PM): Ean's question is deep and philosophical. I think we could ponder it for a long time. ;) swcwgrl (05:31:05:652 PM): that you my son is in 3rd grade and he just has numbers on his work sheet Ean (05:31:22:835 PM): Yeah, it's weird. As I said, I can *do* the technique, but it feels kind of like magic. Ean (05:31:34:691 PM): So we can work on other problems. Mod1 (05:31:35:354 PM): Do you guys want to work on swcwgrl's problem and we wil get back to susbstitution later? Mental_Siege (05:31:42:765 PM): Mod1, sure. Mod1 (05:32:00:884 PM): Good... so could you ask your question again, swcwgrl? Mod1 (05:32:19:297 PM): (and then we can help pOOF!) swcwgrl (05:32:32:388 PM): the work sheet has the numbers 9, 24. 16. 49. 64. 78. 99 swcwgrl (05:33:05:546 PM): I am not looking for you to give the answers but if you could please explain to us Mod1 (05:33:25:756 PM): And what does the worksheet asks you to do? swcwgrl (05:33:32:851 PM): ok sry I was wondering what a square product was system (05:33:43:691 PM): krishara has joined Babylon. p00F (05:33:59:924 PM): i have to simplify ((x^2-3x-28)/(X^2-49)) * ((x^2 +7x)-(3x^2-7x-20)) / ((x^2-9)\(3x^2+14x +15)) Mental_Siege (05:34:09:134 PM): Ean, eventually, you reach certain truths that are self-evident, atomically small, unprovable things, like the common notion if a = b and b = c, a = c. As far as I know, this can't be proven. But it is "obvious." I don't think why substitution works is quite as basic as that... but you could possible start decomposing each step you're taking, and figure out why you believe that step should hold, and be true, instead of the whole process. swcwgrl (05:34:31:517 PM): ok this is 3rd grade work. so they are just asking to circle a number system (05:34:55:893 PM): krishara left the Main chat room. Mod1 (05:35:36:185 PM): Lets try to help swcwgrl, first... anybody has ideas about what a "square product is"? Mental_Siege (05:36:07:972 PM): They probably just mean the square of a number. A square is a number times itself, so you could call it a product. Mod1 (05:36:44:994 PM): does that make sense, swcwgrl? like the square product of a = a*a? p00F (05:37:02:506 PM): it would be what number added to itself 2 times is X p00F (05:37:29:637 PM): er not added multiplied swcwgrl (05:37:35:752 PM): oh ok now i know how to do the work. He usually brings home a student guide book and forgot it today so I as a caring mom took it apon myself to help out . THANK YOU EVERYONE Mental_Siege (05:38:03:376 PM): swcwgl, you're welcome. p00F (05:38:08:836 PM): its just the square of the number swcwgrl (05:38:17:145 PM): bye have a great night system (05:38:19:864 PM): swcwgrl left the Main chat room. Mod1 (05:38:39:072 PM): wow... I am not sure that that was the right answer... were you guys sure? p00F (05:38:56:110 PM): ya Mental_Siege (05:39:02:023 PM): Mod1, it's 3rd grade work. I can't imagine what else they would mean. p00F (05:39:12:321 PM): ok how about mine Mod1 (05:39:15:233 PM): Welll, perhaps we can work no on p00F's question? p00F (05:39:20:210 PM): ((x^2-3x-28)/(X^2-49)) * ((x^2 +7x)-(3x^2-7x-20)) / ((x^2-9)\(3x^2+14x +15)) p00F (05:39:34:188 PM): im scared Mod1 (05:39:48:205 PM): And after that, we will clear the "mistery" of substitution, o.k.? Mod1 (05:40:08:615 PM): WOW!!!! That is quite an equation! p00F (05:40:29:147 PM): i know sorry but i have like a dozen of them to do Mod1 (05:40:36:703 PM): Let me see if I can put it on the whiteboard 'cuase is kind of hard to read in the chat p00F (05:40:37:226 PM): and well..... p00F (05:40:48:918 PM): ok p00F (05:41:02:993 PM): im just suposed to simplify Ean (05:41:31:212 PM): The first thing I notice is that (x^2-3x-28) is (x+4)(x-7). Mental_Siege (05:41:51:765 PM): and x^2 - 49 is (x + 7)*(x - 7) Mod1 (05:41:58:025 PM): You have an eye for squares, Ean! Mod1 (05:42:17:283 PM): Is that first part that I put on the whiteboard, ok, p00F? p00F (05:42:31:824 PM): ya Ean (05:43:16:918 PM): You should meet my family. Ha, ha. p00F (05:43:38:696 PM): nononononono p00F (05:43:50:118 PM): its 3 fractions Mod1 (05:44:15:121 PM): 3 fractions? p00F (05:44:22:181 PM): ummm p00F (05:44:25:550 PM): wait a min p00F (05:44:33:454 PM): lemme type it better Mental_Siege (05:45:00:028 PM): Right. First thing to do ... factor the first fraction. You can cancel the (x - 7) from the numerator and denominator. Mod1 (05:45:03:945 PM): oops! p00F (05:45:33:279 PM): (x^2+7X)/(3X^2-7x-20) that is the second fraction Ean (05:46:24:394 PM): In the first fraction, if you factor the numerator and denominator, you should get (x-7) in both that you can cancel, right? Mod1 (05:47:15:081 PM): like that, p00F? p00F (05:47:28:969 PM): is the denominator (x-7)(x+7) p00F (05:47:41:390 PM): and yes like that Mental_Siege (05:47:58:568 PM): p00f, yes, it's a difference of squares. a^2 - b^2 = (a + b) * (a - b) Mod1 (05:48:00:327 PM): can you put that in the whiteboard, Ean? Ean (05:48:14:425 PM): And in the numerator on the right, you can factor it to x(x+7), which suggests that (x+7) will appear in the denominator. :^D p00F (05:48:17:077 PM): and the 2 fractions there are being multiplied Mental_Siege (05:48:19:725 PM): If you're asking to simplify, one of the first and most basic things to do is factor everything in sight and start cancelling. p00F (05:49:03:660 PM): ok Mod1 (05:49:32:736 PM): very nice... Mental_Siege (05:50:24:406 PM): poof, can you factor the top expression of the same term? p00F (05:50:44:805 PM): the same term? p00F (05:51:26:469 PM): what do you mean the same term? same as what? Mental_Siege (05:51:51:891 PM): each of the "big fractions" with the signs between them can be referred to as a "term." At least, I think that's correct. p00F (05:52:23:413 PM): ok p00F (05:52:36:762 PM): so the (x+7) cancels p00F (05:52:47:689 PM): from both sides p00F (05:52:53:207 PM): ? Ean (05:53:35:211 PM): I think the next thing you want to do is factor the denominator on the left. p00F (05:53:42:051 PM): wait whats the question mark on the bottom factor of the second term p00F (05:54:48:974 PM): o now i see it lol sorry Ean (05:55:03:720 PM): I put that there because I suspect that the denominator will factor into 'something' times (x+7), to cancel the (x+7) in the numerator. Mod1 (05:55:27:994 PM): you "suspect"? p00F (05:55:36:598 PM): lol Ean (05:56:16:610 PM): Yeah, just because it's a made-up problem. p00F (05:56:25:517 PM): so it is (x+4) * (x(x+7) Ean (05:56:34:073 PM): Something is going to cancel over there, and it won't be the x. What does that leave? :^D Mod1 (05:57:06:091 PM): but we need to confirm that "suspiction" Mod1 (05:57:17:025 PM): *suspicion* Mental_Siege (05:57:44:789 PM): If (3x^2 - 7x - 20) factors over the integers, the result will look like (ax + b) * (cx + d), where b and d might be negative numbers. In this case, of b and d, one will have to be positive and the other negative... because... Mental_Siege (05:58:00:387 PM): Because of the -20 on the end. two positives or two negatives multiplied together would give a positive number. p00F (05:58:25:995 PM): wow p00F (05:58:28:201 PM): ok Mental_Siege (05:59:31:612 PM): The easiest way to factor something that looks like 3x^2 - 7x - 20 is to list out the numbers you can multiply together to get the first term and the last term. Mental_Siege (06:00:01:809 PM): In this case, for the first term, you can use 3 and 1. That's about in. For 20, you can use 1,20, 2,10, 4,5 Ean (06:00:04:181 PM): Or you could just use the quadratic formula, right? Mental_Siege (06:00:11:204 PM): Yeah... heh. I always did that. p00F (06:00:36:757 PM): thats what ive seen before p00F (06:00:50:719 PM): and i am realy bad at factoring Mental_Siege (06:02:03:732 PM): Then, to factor, you just kind of try combinations in your head.. like.. umm.. Mod1 (06:02:20:669 PM): and I think we are missing a third fraction on the right, p00F? p00F (06:02:23:658 PM): if theres an lcd im fine but otherwise....... p00F (06:03:31:931 PM): ok the third fraction is (x^2-9)/ (3x^2 + 14x +15)Mental_Siege (06:03:38:683 PM): Ah well. Explaining factoring is a pain. If you've got a lot of these to do, you might be well-served by just practicing some factoring first. Mod1 (06:04:34:164 PM): and is that third fraction multiplied by the other two? p00F (06:04:45:737 PM): no its divided Mod1 (06:05:28:281 PM): it divides the other 2 terms or just the second one? p00F (06:06:18:228 PM): you would just put a divisiot symbol between the 2nd term and the third term Mental_Siege (06:06:29:800 PM): For quadratics, you can use the rational root theorem. I wasn't good at factoring either, and that's what I always did. Take 3x^2 - 7x - 20. Set it equal to 0. The quadratic formula is -b +/- sqrt(b^2 -4ac)/(2a). So, in this case, you plug in the numbers, and you get: x = 4 or x = -5/3 Mental_Siege (06:07:09:768 PM): The rational root theorem (as in, you just have to know this) says that these answers mean that (x - 4) and (3x + 5) are factors of the expression. p00F (06:07:21:431 PM): but what if its like 8x^3-11 p00F (06:09:03:181 PM): no p00F (06:09:09:902 PM): dont do that p00F (06:09:18:973 PM): no big bracket Mod1 (06:09:55:913 PM): don't we need it? p00F (06:09:57:033 PM): how can i expand the canvas horazontaly? p00F (06:10:04:761 PM): no p00F (06:10:08:193 PM): no bracket Mod1 (06:10:12:655 PM): sorry... you can't p00F (06:10:19:205 PM): like taht with no bracket p00F (06:10:36:036 PM): ok Mod1 (06:11:12:097 PM): I see.. but A * B / C is A (B/C) isn't it? p00F (06:11:27:957 PM): no p00F (06:11:44:042 PM): A*B/C p00F (06:11:53:946 PM): is A*B p00F (06:12:01:367 PM): then /C Mod1 (06:12:14:601 PM): what do you guys think? p00F (06:12:23:032 PM): A(B/C) would be AB/AC Mental_Siege (06:12:33:113 PM): I've gotta go. Good luck with the problem! system (06:12:40:519 PM): Mental_Siege left the Main chat room. p00F (06:12:46:484 PM): awww p00F (06:13:19:693 PM): a*b/c is like ab/c p00F (06:13:36:015 PM): pemdas Mod1 (06:13:54:189 PM): Do you agree, Ean? p00F (06:14:09:383 PM): ean is afk i think Mod1 (06:14:21:319 PM): I see... Mod1 (06:14:49:490 PM): So, how close ar e you to a solution?Ean (06:14:53:223 PM): Sorry, y'all kind of lost me... I need to get going. p00F (06:14:57:022 PM): but a*b/c would happe in order so it would be ab/c Ean (06:15:10:089 PM): Bye, all! system (06:15:13:209 PM): Ean left the Main chat room. system (06:15:16:232 PM): Mod1 left the Main chat room. p00F (06:15:22:032 PM): well p00F (06:15:25:174 PM): fine system (06:15:30:560 PM): p00F left the Main chat room.