system (01:48:26:864 PM): rosa has joined Babylon. system (01:50:16:260 PM): rosa left the Main chat room. Mod1 (01:50:17:413 PM): Hi, Rosa!system (01:51:04:510 PM): rosa has joined Babylon. Ian (01:51:27:275 PM): Hi Rosa. Mod1 (01:51:37:579 PM): Hi, Rosa. How are you!rosa (01:51:59:555 PM): please help solve this porblem 4a2-8a3 rosa (01:51:59:797 PM): rosa (01:51:59:797 PM): Ian (01:52:14:202 PM): Are you trying to simplify the expression? rosa (01:52:16:925 PM): hiian rosa (01:52:37:734 PM): no Ian (01:52:51:724 PM): What is it you're trying to do, then? rosa (01:52:53:851 PM): it asked to factor completely Ian (01:53:07:602 PM): Ah, okay. That's a different way to do the same thing. rosa (01:53:15:790 PM): the 2 and the 3 are powers i have no subscript Ian (01:53:49:658 PM): A common way to indicate exponents is a^3 = a*a*a. Ian (01:54:01:630 PM): Are you familiar with the distributive property? rosa (01:54:09:813 PM): yes Ian (01:54:33:262 PM): So could you factor something like 2a - 3a? rosa (01:54:58:580 PM): my answer was 4a(a-2a*a) Ian (01:55:53:272 PM): Suppose we forget about the 4a part. If you have the expression a - 2a^2, can you factor that? rosa (01:56:25:395 PM): you cant factor that it is alreadfy sim plifiedIan (01:56:52:643 PM): Well, what if I write it as 1*a - (2a)*a. rosa (01:57:31:907 PM): please tell me the correct answer your confusing me Ian (01:58:30:506 PM): We'll get back to your problem, I promise. But for now, let's work on something more basic, okay? Ian (01:59:36:254 PM): The expression 2a - 3a can be factored, because the two terms have a common factor, which is 'a'. Ian (01:59:42:839 PM): So if you factor it, what do you get? rosa (02:00:28:795 PM): a(2-3) Ian (02:01:24:308 PM): Excellent. Ian (02:01:50:121 PM): What if we start with 2a^2 - 3a^2? rosa (02:03:38:595 PM): a*a(2-3) Ian (02:03:52:977 PM): Perfect. system (02:04:00:968 PM): greg has joined Babylon. greg (02:04:07:912 PM): heygreg (02:04:09:823 PM): anyone there?Ian (02:04:12:430 PM): Now let's try one more: 2*a^2 - 3a*a^2. greg (02:04:28:823 PM): great how are you?greg (02:04:33:419 PM): i got a probability questiongreg (02:04:47:257 PM): and i found how to do it on this website but it didnt give a great explanationgreg (02:04:54:609 PM): anyone interested in helping me out?greg (02:05:11:340 PM): nope, any idea of expected wait time?system (02:05:55:892 PM): Mod1 left the Main chat room. rosa (02:06:11:216 PM): please refrase the last part of eguation system (02:06:17:615 PM): Mod2 entered the Main chat room. Ian (02:06:49:364 PM): We can write it as (2)a^2 - (3a)a^2. Ian (02:07:10:223 PM): So we have [something]*a^2 - [something else]*a^2. greg (02:07:14:912 PM): sure!system (02:07:22:288 PM): greg left the Main chat room. rosa (02:07:46:580 PM): okay you lost me can we go back to my original question m,y time is running low Ian (02:08:00:987 PM): We're almost to your original question. You're just one step away. rosa (02:09:10:487 PM): so rosa (02:09:17:389 PM): whts rosa (02:09:21:837 PM): nezt Ian (02:09:23:398 PM): Because your original question is the same as (4)a^2 - (8a)a^2. system (02:09:58:751 PM): greg has joined Babylon. system (02:10:04:789 PM): greg left the Main chat room. Ian (02:10:46:705 PM): We can try looking at yours another way. 4a^2 - 8a^3 is the same as rosa (02:10:47:807 PM): please help my answer to my question is 4a*a(-2a) rosa (02:10:58:431 PM): is it correct Ian (02:11:06:388 PM): It's not correct. rosa (02:11:24:681 PM): why rosa (02:11:30:685 PM): where Ian (02:11:35:272 PM): I'm trying to help you see why. rosa (02:11:35:722 PM): ist my sing rosa (02:11:57:127 PM): but your running around in circlesIan (02:12:29:502 PM): Your problem is 4a^2 - 8a^3, right? rosa (02:12:36:355 PM): if i see the correct answer i can deduce where i went wrong my self rosa (02:12:53:070 PM): yes Ian (02:13:10:623 PM): That's the same as (4)*a^2 - (8a)*a^2. rosa (02:13:24:310 PM): yes ]\Ian (02:13:41:772 PM): Those two terms have something in common, which can be factored out using the distributive property. What do they have in common? rosa (02:14:11:259 PM): a*a Ian (02:14:25:908 PM): Right. So what do you get when you factor that out? rosa (02:15:42:991 PM): a*a(4-8a Ian (02:15:55:477 PM): Perfect! You're almost there. Ian (02:16:21:313 PM): Let's write that as a*a(4*1 - 4*2a). Ian (02:16:38:946 PM): Now the two terms in the ()'s have something in common that can be factored out. What do they have in common? rosa (02:17:01:588 PM): 2a*a(2-4a) Ian (02:17:28:159 PM): Do they have an a in common? Look at them again: 4*1 and 4*2a. Ian (02:17:58:630 PM): Oh, sorry! You're right. Ian (02:18:04:574 PM): I misread what you wrote. rosa (02:18:26:707 PM): 4A*A(1-2A) Ian (02:18:39:819 PM): Perfect. Ian (02:18:42:671 PM): Exactly right. Ian (02:18:46:797 PM): Does it make more sense now? rosa (02:19:12:705 PM): I GUESS Ian (02:19:20:991 PM): Let's try another one, to see if it does. Ian (02:19:40:240 PM): What about 9b^3 - 6b^2? rosa (02:20:10:128 PM): DONT TAKE IT THE WRONG WAY BUT YOUR THE ONLY PAIN IN THE ASS HA HA SEE YOU LATER:) Ian (02:20:44:011 PM): What would be the right way to take that? :^D rosa (02:21:28:345 PM): DUST YOUR SHOULDERS OFF IKNOW WERE YOUR COMING FROM I Appreciate your help rosa (02:21:38:320 PM): thanx rosa (02:21:46:573 PM): see yah Ian (02:21:50:764 PM): You're welcome. Ian (02:21:59:358 PM): Bye. system (02:22:33:071 PM): rosa left the Main chat room. Ian (02:22:40:315 PM): So, apart from the fact that she wanted me to just tell her the answer, that went pretty much the way I thought it would... system (02:43:06:624 PM): dana16 has joined Babylon. system (02:43:24:945 PM): dana16 left the Main chat room. system (02:43:41:454 PM): dana16 has joined Babylon. system (02:44:37:085 PM): dana16 left the Main chat room. system (03:00:32:221 PM): Iain left the Main chat room. system (03:00:37:331 PM): Ian left the Main chat room. Mod2 (03:25:23:384 PM): Ian?system (03:27:25:358 PM): Johann has joined Babylon. system (03:56:21:566 PM): mijitpride has joined Babylon. mijitpride (03:56:56:690 PM): is anyone here? Mod2 (03:57:04:883 PM): Hi mijit!mijitpride (03:57:13:209 PM): watsup mijitpride (03:57:31:865 PM): how old are you guys? Mod2 (03:57:48:068 PM): Very well.. are you having Math problems?system (03:58:25:372 PM): Johann left the Main chat room. mijitpride (03:58:27:329 PM): somewhat .. but not necessarily a problem ... Mod2 (03:58:42:846 PM): how come?mijitpride (03:58:53:156 PM): im only in 11th grade so if this all sounds elementary bare with me .... Mod2 (03:59:40:618 PM): I see... sure we decided to start with arithmetic and algebra. Dr. Math gets lots of thosemijitpride (03:59:51:889 PM): me and my math teacher discovered e^i*pi+1=0 and weve been trying to break it down into simpler terms .. can you help Mod2 (04:00:18:679 PM): 11th grade is certainly past that... you are in Calculus now, right?mijitpride (04:00:36:478 PM): no .. pre calc ... Mod2 (04:00:44:414 PM): you "discover" it? What do you mean?mijitpride (04:00:51:290 PM): few 11th graders are in calculus .. Mod2 (04:01:45:426 PM): I see..mijitpride (04:02:00:857 PM): i just read it in a book and asked him if he knew much about it mijitpride (04:02:26:852 PM): can you break it down into simpler terms Mod2 (04:03:34:549 PM): is the expression that I put in the blackboard the one you were thinking of?mijitpride (04:03:42:967 PM): yea mijitpride (04:04:00:971 PM): actually no mijitpride (04:04:27:533 PM): its ... e^(i*pi)+1=0 Mod2 (04:05:09:263 PM): I see... that sounds betterMod2 (04:06:04:734 PM): did you search the Dr. Math Archive for the relationship between e and pi?mijitpride (04:06:42:729 PM): yes .. and i read one of the entries on it for about 2 minutes until he concluded that there was no relationship .. i think? Mod2 (04:07:35:452 PM): interesting... I am trying to plot your equation in Excel but what I wrote in the whiteboard does not add up to 0... with i=1, 2, 3, 4, ...mijitpride (04:08:22:421 PM): but i is meant to be the "i" in math .. not a variable ... its the square root of -1 Mod2 (04:08:56:054 PM): Ah! I was reading it all wrong!!! Now it gets interesting! system (04:09:20:361 PM): mijitpride left the Main chat room. system (04:10:17:048 PM): mijitpride has joined Babylon. mijitpride (04:10:37:854 PM): are you a person or a computer? Mod2 (04:11:25:059 PM): what do u think?mijitpride (04:11:34:678 PM): a computer system (04:12:55:880 PM): Test has joined Babylon. mijitpride (04:13:03:676 PM): watsup test Test (04:13:29:611 PM): What are you working on? Mod2 (04:13:32:962 PM): Hi, Test!system (04:13:50:311 PM): Ian has joined Babylon. Mod2 (04:13:54:387 PM): we wer talking about a wonderful formula that mijit foundMod2 (04:14:13:328 PM): Hi, Ian!Test (04:14:18:646 PM): Hi. mijitpride (04:14:43:215 PM): its probably gonna sound elementary but im only in pre calc in high school ... me and my teacher were trying to breakdown eulers e^i*pi +1=0 formula into simpler terms mijitpride (04:16:29:368 PM): any input? Mod2 (04:16:38:785 PM): Is the formula in the canvas the same as yours, mijit?mijitpride (04:16:44:495 PM): YESSS Ian (04:17:08:679 PM): What other form were you starting with? system (04:17:30:418 PM): Test left the Main chat room. mijitpride (04:18:08:070 PM): e^i*pi=-1 and therefore e^i*x=cosx+sinx .. i think thats it mijitpride (04:18:47:357 PM): but i think that only works with incriments of pi Ian (04:19:02:565 PM): That's what you mean by 'therefore'? mijitpride (04:19:48:560 PM): are you both computers? cause its annoying how slowly you type mijitpride (04:20:21:474 PM): and ive been here for about 10 minutes and neither of you have said anythign yet except restating what i say to you Ian (04:20:39:974 PM): Sorry, mijitpride (04:20:48:848 PM): are you both computers? Ian (04:21:00:824 PM): I'm wondering what you mean by 'therefore'. You just mean that it works for multiples of pi, right? mijitpride (04:21:31:241 PM): mijitpride (04:21:33:842 PM): mijitpride (04:22:40:177 PM): please say something Ian (04:22:48:765 PM): I'm here. Ian (04:23:02:718 PM): Who drew the equation down there? mijitpride (04:23:53:782 PM): so why are you here ... you toil away and occasionally answer a few high school math questions .. usually from some moron whos asking about factoring a quadratic mijitpride (04:23:56:217 PM): i did mijitpride (04:24:06:820 PM): what do you know about the formula i drew in the canvas Mod2 (04:24:24:794 PM): sorry, mijit I was having problems with my systemIan (04:24:45:025 PM): It's not really toiling. It's fun, actually. mijitpride (04:25:02:112 PM): ok .. so what do you know about this equation Ian (04:25:05:068 PM): Right now, I'm realizing that I don't know all that much about Euler's equation. Ian (04:25:22:953 PM): What occurs to me is that there are series expansions for sine and cosine... mijitpride (04:27:24:196 PM): how do you factor the equation on the canvas Mod2 (04:27:31:815 PM): mijit you might want to check this URL (in a separate window)Mod2 (04:27:34:277 PM): http://answers.google.com/answers/threadview?id=455688Ian (04:27:39:980 PM): I guess from one point of view, the version e^(i*pi) = -1 is already simple, because you can take the log of both sides. mijitpride (04:28:05:475 PM): but you cant take the log of a negative number Ian (04:28:16:403 PM): Not if you stay inside the real numbers, no. mijitpride (04:28:27:691 PM): well not necesarrily simpler btu more of finding out why that equation is true Ian (04:28:41:343 PM): It's sort of like not being able to subtract 5 from 3... unless you use a bigger conception of 'number', i.e., you start using negatives. mijitpride (04:29:08:691 PM): very true ... so what would the log of negative 1 be? Ian (04:29:35:902 PM): It looks like ln[e^(i*pi)] = ln[-1] Ian (04:29:47:445 PM): so i*pi = ln(-1) mijitpride (04:29:49:781 PM): noo ... Ian (04:30:05:188 PM): No? mijitpride (04:30:25:324 PM): wouldnt it be (i*pi) ln(e) = ln(-1)Ian (04:31:06:602 PM): Well, the logarithm is the inverse of the exponent, so ln(e^whatever) = e^ln(whatever), right? mijitpride (04:31:57:138 PM): ohh .. i didnt realize thats how you typed it .. mijitpride (04:31:59:588 PM): so either way ... what is ln(-1) Ian (04:32:13:127 PM): If we're doing this right, it's just i*pi. Ian (04:33:04:484 PM): Which would explain why you can't find a _real_ log of a negative number. mijitpride (04:33:07:862 PM): whooah ... so ln(-1) = i*pi .. ??? Ian (04:33:17:082 PM): That's certainly how it looks. mijitpride (04:33:24:381 PM): thats so cool Ian (04:33:35:069 PM): Kind of weird where notation can take you, isn't it? mijitpride (04:33:43:899 PM): is it the same for log(-1)? Ian (04:34:03:031 PM): Well, now you have a different base, so I'd expect a different value. Ian (04:34:18:532 PM): But it would still be imaginary. mijitpride (04:34:26:926 PM): do you knwo what that value is? Ian (04:34:33:218 PM): I guess you'd just use the 'change of base' formula, which I can never remember. Ian (04:34:52:024 PM): Have you learned it yet? I always have to look it up. mijitpride (04:35:17:727 PM): i think i learned it .. but i cant remember sorry mijitpride (04:35:41:413 PM): 10^x=-1??? Ian (04:35:44:486 PM): It would turn out to be something like i*pi*(ln(e)/ln(10)) Ian (04:36:05:341 PM): Just multplied by a scale factor. Maybe the scale factor is ln(10), or log(e). mijitpride (04:36:22:092 PM): i gotcha ... mijitpride (04:36:47:099 PM): are you a computer or a person? Ian (04:37:10:234 PM): Well, I studied artificial intelligence, so to me there's not much difference between the two. mijitpride (04:37:57:185 PM): well ... whether or not theres a big difference is irrelevant ... Ian (04:38:44:948 PM): I guess what I'm saying is that either I'm a computer made of silicon, or a computer made of meat. But either way... mijitpride (04:39:08:941 PM): so anyway .. back to math ... teach me something Ian (04:39:24:413 PM): What would you like to know? Is this your first exposure to complex numbers? mijitpride (04:40:24:587 PM): ehh ... i have some experience with them ... but very simple equations ... such as factoring quadratics inot a+bi form ... but in retrospect im only in pre calc Ian (04:41:41:316 PM): Yeah, I was surprised that you were talking about Euler's equation. Have you had any trig? mijitpride (04:42:01:340 PM): why .. is eaulers equation below pre calc or past it Ian (04:42:57:411 PM): Good question! You'd know that better than I would, though. Ian (04:43:18:071 PM): I never understood what 'pre-calculus' actually meant. mijitpride (04:43:32:898 PM): well .. were you surprised because it was advanced for pre calc or because pre calc is well past it Ian (04:43:41:117 PM): Oh, it seemed advanced. mijitpride (04:44:17:512 PM): well i only know of it because i just finished reading a book on fermats last theorem ad it was in there Ian (04:45:14:627 PM): So you've already been through stuff like how polynomials can have either real or complex roots? Ian (04:45:28:830 PM): Or both, actually. mijitpride (04:46:05:195 PM): how can they have both mijitpride (04:46:20:037 PM): im not doubting you im just inquiring mijitpride (04:46:42:501 PM): what math are you in now?? mijitpride (04:47:46:732 PM): you there? Ian (04:47:51:942 PM): Sorry, yea. Ian (04:47:57:959 PM): It's a good question. Ian (04:48:33:349 PM): If we have a parabola, like that mutant one I just drew... system (04:48:40:286 PM): .. has joined Babylon. mijitpride (04:48:41:921 PM): yea .. Ian (04:48:43:802 PM): It hits the x-axis at two points. Ian (04:48:48:949 PM): Those are the roots, right? mijitpride (04:48:54:260 PM): yea Ian (04:49:14:504 PM): We'd have something like (x - 2)^2 - 3 = y Ian (04:49:30:411 PM): But what if it never touches the x-axis? mijitpride (04:49:40:050 PM): no i understand that mijitpride (04:49:54:301 PM): but how can they be both imaginary and real Ian (04:49:56:966 PM): Okay, so let's move from a quadratic to a cubic. We could have a cubic that looks like Ian (04:49:57:170 PM): Ian (04:50:26:462 PM): That has three real roots. Ian (04:50:31:522 PM): But if it looks like t his, Ian (04:50:50:424 PM): that has one real one, and two imaginary ones. system (04:50:56:366 PM): tripleplay777 has joined Babylon. Ian (04:51:09:912 PM): Or were you thinking I meant that one root could be both real and imaginary? mijitpride (04:51:18:607 PM): the imaginary roots of that second cubic is just hte max and min? mijitpride (04:51:59:677 PM): but a quadratic could never have real an imaginary roots .. could it? mijitpride (04:52:30:398 PM): well anyway ... teach me something new mijitpride (04:52:39:761 PM): im eager to larn Ian (04:52:47:310 PM): Well, that's a really good question. What would it have to look like for that to happen? tripleplay777 (04:52:56:750 PM): Can someone explain me the concept of constant and increasing in a functionmijitpride (04:53:07:902 PM): it would have to go through a roatation ... woul it not? Ian (04:53:26:619 PM): What do you mean? mijitpride (04:53:46:203 PM): hold on .. i had a thought Ian (04:53:46:684 PM): Mijit, do you want to take a moment to help Triple with his question? Ian (04:53:52:510 PM): What thought? mijitpride (04:54:31:878 PM): nevermind .. i thought if you rotated it .. but if you think about the quadtratic formula .. it owuld be impossible for the roots to be imaginary and real in the same quadratic Ian (04:54:49:997 PM): That's right. The trick is proving it. :^D Ian (04:55:17:831 PM): Triple, do you mean you want to know what a 'constant function' is, and what an 'increasing function' is? tripleplay777 (04:56:54:318 PM): how do you identify where it is increasing, decreasing, or constant on a function?mijitpride (04:57:02:936 PM): you just graph it mijitpride (04:57:24:453 PM): well go with cubic tripleplay777 (04:58:51:368 PM): well would the domain be -infinity to infinity then?Mod2 (04:59:03:042 PM): (Just to clarify... if you hit "clear the canvas" it erases it for everyone so make sure everyone agrees with that before doing it)mijitpride (04:59:04:904 PM): yea ... so thin kabout it tripleplay777 (04:59:29:099 PM): increasing on [0,infinity)?mijitpride (04:59:29:540 PM): if the function is sadi to be increasing .. the y value should be .. increasing right? Ian (04:59:33:865 PM): Triple, by 'domain' do you mean the domain where it's increasing? mijitpride (04:59:48:977 PM): yes and no (to triple) tripleplay777 (05:00:18:321 PM): then where would the function be increasing?mijitpride (05:00:36:879 PM): it increasing from (-infinity,-1) and also from (.5, infinity) on this graph mijitpride (05:00:55:379 PM): and it is constant from (-1,.5) Ian (05:01:10:700 PM): Maybe it would be useful to try to define what we mean by 'increasing'? mijitpride (05:01:24:954 PM): basically think of it as pertaining to the y value .. if the y value is incerasing then the function is increasing ... understood? Ian (05:01:42:657 PM): But it's implied that we're moving left to right, isn't it? mijitpride (05:02:34:735 PM): well thats how we reas mathematical graphs .. is it not? Ian (05:02:40:666 PM): Triple, are you wondering if something can be increasing where it's negative? tripleplay777 (05:02:50:876 PM): yesIan (05:03:23:406 PM): Can you see that a change from, say, -5 to -3 is an increase? mijitpride (05:03:23:829 PM): it can be increasing even though its in negative values mijitpride (05:04:06:019 PM): what mat hare you in triple? tripleplay777 (05:04:32:130 PM): Pre-Calculusmijitpride (05:04:38:161 PM): cool cool mijitpride (05:04:42:587 PM): i am too Ian (05:05:56:580 PM): I can see where, if you think of x as going away from the origin, it would seem like the function increases to the right, but decreases to the left... mijitpride (05:06:25:098 PM): yea .. i can see how that would happen mijitpride (05:06:43:343 PM): you just have to think of graph as flowing from -infinity to infinty Ian (05:06:54:071 PM): I guess it's one of the reasons you have to spend so much time making sure you have definitions straight, so everyone is using the same words the same way. Ian (05:07:16:584 PM): Triple, have you learned about slopes yet? mijitpride (05:07:28:234 PM): oooh .. good idea Ian tripleplay777 (05:07:44:405 PM): no, rapping up on functions right nowmijitpride (05:07:58:073 PM): you havent learned slopes yet?? Ian (05:08:00:731 PM): But how about slopes of lines, back in algebra? tripleplay777 (05:08:28:790 PM): oh yeahIan (05:08:53:016 PM): So you know about positive and negative slopes? tripleplay777 (05:09:13:909 PM): i don't believe i know about negative slopesmijitpride (05:09:54:019 PM): are you in college ian? Ian (05:10:07:287 PM): Something like that. Ian (05:10:21:925 PM): Triple, in the lower right, the two lines... tripleplay777 (05:10:42:479 PM): oh okay...Ian (05:10:47:909 PM): One has a positive slope, one has a negative slope. Ian (05:11:00:168 PM): The one with the positive slope is 'increasing'. Ian (05:11:08:289 PM): The one with the negative slope is 'decreasing'. Ian (05:11:23:192 PM): Does that make sense? mijitpride (05:11:28:762 PM): what college .. if you dnot mind me asking Ian (05:11:41:617 PM): I think we're not supposed to share personal information like that... mijitpride (05:12:14:854 PM): oh shit .. sorry about that ... i forgot mijitpride (05:12:36:308 PM): what math you in .. calc .. calc2 calc3 calc4?? tripleplay777 (05:12:51:985 PM): oh okay what about...Ian (05:13:08:938 PM): I'm trying to learn multivariate calc... mijitpride (05:13:26:580 PM): oh really .. so youve already done the first of the calcs? Ian (05:13:37:069 PM): Triple, you drew y = x? Do you think it's increasing, or decreasing? tripleplay777 (05:13:56:808 PM): increasingtripleplay777 (05:14:14:121 PM): or is it constantIan (05:14:41:867 PM): Interesting question. What makes you think it might be constant? tripleplay777 (05:15:29:780 PM): it doesn't change directionIan (05:15:50:491 PM): Ah, okay. That makes sense. Right, the slope is constant! Ian (05:16:05:598 PM): But the function isn't. It can be kind of hard to keep those straight. tripleplay777 (05:18:21:497 PM): how would you find a domain of something like...Ian (05:19:18:792 PM): I guess if you're gonna find something, you'd better have some idea of what it is. When I say 'domain', what does that mean to you? mijitpride (05:19:19:855 PM): to find tha domain just set the denominator equal to zero .. that will give you the asympotote (vertical at least) Ian (05:19:58:760 PM): If you set it to zero, won't it be undefined? tripleplay777 (05:20:41:258 PM): so it is not equal to zero?Ian (05:21:57:335 PM): Sometimes it's easier to look at simple examples. Triple, can you see what the domain of y = 1/x would be? mijitpride (05:23:57:229 PM): so triple ... explain to me what a domain is system (05:24:03:685 PM): tripleplay777 left the Main chat room. mijitpride (05:24:12:489 PM): i guess not mijitpride (05:24:36:859 PM): so can you teach me something new? sorry to ask something so vague .. but i just enjoy math Mod2 (05:24:40:216 PM): wow... you guys scared him! ;-)Ian (05:25:02:471 PM): Man, didn't mean to do that. Maybe it's just technical problems, though. Mod2 (05:25:22:533 PM): trueMod2 (05:25:36:713 PM): how do you like this type of chat room, mijit?mijitpride (05:25:54:936 PM): i actually stumbled upon it today and i think its pretty cool Ian (05:25:56:876 PM): So, Mijit, do you know of any ways other than graphing to know when a function is increasing or decreasing? system (05:26:13:975 PM): connor has joined Babylon. Mod2 (05:26:31:210 PM): Hi, connor! welcome!Ian (05:26:40:957 PM): Hi Connor. mijitpride (05:26:55:615 PM): well .. you could just analyze the equation unless its too complex .. in general though .. i just plug in different x values and not the trends connor (05:26:56:395 PM): hiIan (05:27:09:292 PM): That's one of the things you learn to do in calculus. mijitpride (05:27:29:261 PM): is this chat open every day Mod2 (05:27:38:117 PM): do you have a math question, connor?mijitpride (05:28:29:097 PM): if this chat was open 24/7 .. i think i would skip scholl just to tal to people about math connor (05:28:45:186 PM): Yeah guys. I was hoping you could help me with something really quick. I need a word to match this defenition. What's an arrangement or listing of objects in which order is not important?mijitpride (05:29:16:109 PM): your doing probability .. are you not? connor (05:29:35:186 PM): yeupmijitpride (05:29:37:614 PM): im gonna say its a permutation connor (05:29:49:932 PM): the third letter is an Nconnor (05:30:02:564 PM): I'm in 6th grade, so it won't be too difficultconnor (05:30:19:297 PM): it's 11 letters too, if that helpsmijitpride (05:30:27:904 PM): im really not sure ... sorry connor (05:30:32:279 PM): thanks guysIan (05:31:03:676 PM): Isn't a permutation when you switch the order of things? Like abc, cab, bac are all permutations of the letters 'a', 'b', and 'c'? Ian (05:31:31:375 PM): Are you sure the third letter isn't m, and not n? mijitpride (05:31:55:798 PM): i dont know the name .. but it might be these calculations connor (05:32:04:335 PM): sorry it is a MIan (05:32:10:578 PM): Right - same combination, different permutations. Mod2 (05:32:20:547 PM): and abc is the same "combination" as cab isn't it?Ian (05:32:28:769 PM): So, there are two possibilities. Ian (05:32:45:874 PM): One is 'set', which has 11 (base 2) letters. connor (05:32:53:748 PM): combination fitsMod2 (05:32:54:684 PM): but these words don't have an N in the third place!connor (05:32:55:609 PM): thanks guysIan (05:32:59:081 PM): I love jokes involving bases. :^D mijitpride (05:33:05:534 PM): im not sure which is which but either permutation or combination .. one of them accounts only for abc and the other accounts for abc, acb, bac, cab, cba, bcaa connor (05:33:10:153 PM): that worksIan (05:33:12:359 PM): But 'combination' has an M in the third place. Mod2 (05:33:42:871 PM): Ah! I missed that! mijitpride (05:33:49:162 PM): its definately permutation that accounts for different letterings Ian (05:33:55:555 PM): It can be a little funny, 'cause in 'real life' we use combination to mean both, like the combination of a safe. Mod2 (05:34:05:326 PM): So you know how many combinations you can make with the letters M-A-T-H, connor?Ian (05:34:16:121 PM): 32-12-42 is different than 12-42-32. mijitpride (05:35:00:721 PM): thats permutation system (05:35:06:082 PM): lilfeerie has joined Babylon. Mod2 (05:35:10:880 PM): what's that, mijit? Looks like a 4 that is so great you put an exclamation mark there!connor (05:35:15:839 PM): I have one more that I am stuck on. It says what is the process of acting out a problem. this has ten lettersIan (05:35:31:239 PM): Hi lilfeerie, welcome. Mod2 (05:35:32:891 PM): Hi, lilfeerie, welcome!lilfeerie (05:35:40:516 PM): hi guys mijitpride (05:35:46:859 PM): hi lilfeerie (05:35:52:439 PM): good Mod2 (05:35:55:315 PM): We are helping connor and we can take your question in a minute...lilfeerie (05:36:05:272 PM): cool mijitpride (05:36:14:821 PM): any questions lilfeere Mod2 (05:36:18:953 PM): "acting out a problem"?lilfeerie (05:36:30:320 PM): no well yes Ian (05:36:54:223 PM): Do you have any of the letters? mijitpride (05:37:07:025 PM): what is it connor (05:37:07:522 PM): fifth letter is Llilfeerie (05:37:18:373 PM): bye guys mijitpride (05:37:27:524 PM): what the question lilfeerie (05:37:36:405 PM): this is a little boring system (05:37:42:077 PM): lilfeerie left the Main chat room. system (05:37:45:102 PM): mijitpride left the Main chat room. Ian (05:37:45:463 PM): Oh, okay, I know what it is. Mod2 (05:38:26:044 PM): what is it?Mod2 (05:39:02:720 PM): do you have any ideas, connor? Perhaps you have studies something like this in class.connor (05:39:41:334 PM): Not really, I have all of the other questions answered but could not find this one or the other one that you helped me onMod2 (05:39:43:409 PM): connor?Ian (05:40:25:328 PM): Here's an other hint: What would you call the world in a video game? connor (05:40:56:587 PM): 3dIan (05:40:58:372 PM): Or the world of the Matrix, if you've seen that movie. system (05:41:19:672 PM): mijitpride has joined Babylon. connor (05:41:37:294 PM): i have seen all the moviesmijitpride (05:41:50:283 PM): yea i got disconnected Ian (05:41:54:464 PM): It's also a word meaning 'not real'. Mod2 (05:42:43:179 PM): The only thing that comes to mind is that when you "act out" is not real, right?connor (05:43:12:835 PM): i dont nomijitpride (05:43:30:519 PM): show me some more math ian Mod2 (05:43:42:079 PM): Ian, gives a couple of more letters...mijitpride (05:44:07:526 PM): undoubtedly ... now that i know about this .. ill be on here every chance i get mijitpride (05:44:30:456 PM): simulation? Mod2 (05:44:50:810 PM): WOW!!! that fits! How did you figure it out?connor (05:44:56:511 PM): thanksmijitpride (05:45:07:397 PM): no problem Mod2 (05:45:18:152 PM): how do you "Simulate" a problem?mijitpride (05:45:25:202 PM): beats me Mod2 (05:45:43:687 PM): have you learned about simulations, connor?connor (05:45:54:385 PM): yesconnor (05:46:18:104 PM): i just forgotconnor (05:47:06:484 PM): g2g to do choresMod2 (05:47:37:117 PM): o.k. connor. We will be here next Thursday!connor (05:47:46:797 PM): okMod2 (05:47:48:025 PM): Thanks to mijitpride, tooconnor (05:47:54:463 PM): byeMod2 (05:48:18:642 PM): We are going to have to close this chat room now but you are welcome to join us in a weeksystem (05:48:28:586 PM): connor left the Main chat room. Mod2 (05:48:32:847 PM): Keep an eye on the Dr. Math page!Ian (05:48:57:210 PM): That'll be cool. Mod2 (05:49:03:352 PM): Thanks a lot, Ian and mijitpride!Ian (05:49:05:449 PM): Thanks for coming by! mijitpride (05:49:10:261 PM): thanks so much for this oppurtuntiy Ian (05:49:15:269 PM): Thanks Mod2! mijitpride (05:49:28:802 PM): do you have a screen name on instant messanger i can cotact you on .. or not information? system (05:49:35:721 PM): Courtney has joined Babylon. system (05:50:36:716 PM): .. left the Main chat room. mijitpride (05:50:40:200 PM): i figured ... will do .. and ill see you next thursday Mod2 (05:51:26:004 PM): Oops, Courtney we were about to close down the room...Mod2 (05:51:33:138 PM): do you have a quick question to ask?mijitpride (05:52:50:695 PM): bye guys Mod2 (05:53:05:077 PM): O.K. I don't want to be rude but the server will be down in 30 secs...system (05:53:10:469 PM): mijitpride left the Main chat room. Mod2 (05:53:13:098 PM): see you next Thursday...system (05:53:18:679 PM): katire has joined Babylon. katire (05:54:06:404 PM): i was wondering if anyone here could help me katire (05:54:50:197 PM): i need to figure out how to factor 2+x^(-1/2)+1/4x^(-1)katire (05:55:12:294 PM): I treid completing the square katire (05:55:20:005 PM): do you know Ian (05:55:20:358 PM): Katire, try writing to Dr. Math, and I can help you there... katire (05:55:29:878 PM): ? Ian (05:55:35:932 PM): http://mathforum.org/dr.math/ask/submit.html katire (05:55:36:309 PM): what is Dr. Mathkatire (05:55:52:093 PM): thank youMod2 (05:56:42:421 PM): We will be here next Thursday 3:00pm to 5:30 pm Estern Standard Time!system (05:57:49:672 PM): Courtney left the Main chat room. system (05:57:51:637 PM): Ian left the Main chat room. system (05:58:38:371 PM): katire left the Main chat room. system (05:58:38:641 PM): Mod2 left the Main chat room.