Elementary POW, April 15-19, 1996


Elementary POW Problems || April-June, 1996 Problems || Elementary POW Main Page

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Elementary Problem of the Week, April 15-19,1996

This week's problem was submitted by Jody Newman, Center School, Stow MA.

Once there lived a farmer, his wife, and their three sons.  When the
farmer died, his will said that the eldest son was to receive one-half of
what he owned, the middle son was to receive one-third, and the youngest
son was to receive one-ninth.  All the farmer owned, however, was
seventeen horses.  And try as they might, the three sons could not figure
out any way to divide the seventeen horses by their fathers wishes.

"Don't worry," their mother told them. "We can solve this with a little
help."

She went to the neighboring farm and borrowed a horse.  Then with a total
of eighteen horses, she gave the eldest son one-half, or nine horses.
She gave the middle son one-third, or six of the horses.  And she gave
the youngest son one-ninth, or two of the horses.

"There," she said.  "Nine plus six plus two makes the seventeen horses
your father left you."  And she returned the eighteenth horse to the
neighbor.

How did she do it?

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Correct Solutions submitted by:

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Amy Forster,age 11, grade 7, home
schooling,Cygnet, Australia,email jwilkins@tassie.net.au 

Wilkins/Forster family
Crooked Tree Point.Cygnet.
Tasmania.Australia 7112.
ph.[002] 951456

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Mike, Nick, Julia, Meghan L., Meghan R.
Grade 4
Ms. Seager
Bagnall School, Groveland, MA

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Brent Durkee, Jon Gunn
Grade 6
Mrs. Caruso
Bagnall School, Groveland, MA

Ian Gugger
Grade 6
Mrs. Caruso
Bagnall School, Groveland, MA

Colin Stokes
Grade 6
Mrs. Caruso
Bagnall School, Groveland, MA

Brian G. and Craig D.
Grade 6
Mrs. Caruso
Bagnall School, Groveland, MA

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Cory, Mike M., Brian Parks
Grade 4
Ms. Arria-Lucey
Bagnall School, Groveland, MA

Alison Morse, Kerry Sniegoski, Heather Quigley Grade 4
Ms. Arria-Lucey
Bagnall School, Groveland, MA

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Dave Neely - 11
Jason Imbrogno - 11
Burchfield Elementary School
Pittsburgh, Pennsylvania 

Kirstan Gides
Krista Ziegler
Lindsay Rockot
Grade 5b
Burchfield Elementary School
Pittsburgh, Pennsylvania 

Stephen Viale 
grade  5
Burchfield Elementary School
Pittsburgh, Pennsylvania 

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Mrs. Fisher's fourth/fifth grade class
Aliso School
Carpinteria, California.

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Margrethe, Leslie, and Marie
Grade 4
Leal School
Urbana, IL

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Name: Beth Jaxon
Grade: 5-6
Teacher's name: Becky and Greg Jaxon
School: Learners Unlimited (H.O.U.S.E.)
Location: Champaign, IL

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Rebecca, Grade 3
Nancy Kaye
Lincoln Elementary
Burlingame, CA

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Steve Moleski
Mr. Underkoffler's fifth grade class
Arrowhead School
Methacton School District

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Nicole Petrancosta, Katie Kleppick,Brittany Kress
Marzolf 5A
Pittsburgh, PA

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Dan, Matt, Patrick, Kate, Anthony and Todd
Miss Duggan's fourth grade class 
Munsey Park School
Manhasset, NY

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Anita Minakyan, Matt Burke, Ryan Drago and Jeffrey Chin
Mrs. Hirn's class 
Munsey Park School
Manhasset, NY

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Ashoke Khanwalkar, grade 3
Western Salisbury School
Allentown, PA 18103

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Kristen Dempsey, Elizabeth Phommathep, John Hale
George L. Hess Educational Complex
Fifth Grade - Ms. Blair
Mays Landing, NJ 

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Highlighted Solutions

****************************

Amy Forster,age 11, grade 7, home
schooling,Cygnet, Australia,email jwilkins@tassie.net.au 

Wilkins/Forster family
Crooked Tree Point.Cygnet.
Tasmania.Australia 7112.
ph.[002] 951456

17 is a prime number so it can't be divided by anything.You need to find a
number divisible by 1/2,1/3, 1/9. ie.divisible by 2,3,and 9.

18=1/2 (of 18) + 1/3(of 18)+ 1/9 (19)
= 9+6+2
= 17+1 left over

It works because the extra horse from the neighbour makes an even number
for dividing in half. Also,by dividing an even number by 2 odd and 1 even
number,you get a sum which is odd+even+even =odd,so there is one left
over,so you can return the neighbours horse. 

I explored other numbers divisible by 9,3 and 2 and found this pattern: 

Let O.N. =Original Number
Let N.H. = Neighbours Horse



Amount less than
O.N.O.N. + N.H.1/2
1/31/9TotalO.N. + N.H.

1718
96217
1
3536
1812434
2
5354
2718651
3
7172
3624868
4

As the original numbers increase, there is an extra horse left over. So for
example,if the boys had to share 53 horses and borrowed 1 horse from the
neighbour,they would end up giving 3 horses back to their neighbour,so the
neighbour would gain 2 horses!

I thought this problem was interesting because it was a bit like using a
catalyst in chemistry.Is there an area in maths where you change a
number(eg make it bigger)so you can solve a problem,then remove it-maybe
catalyst numbers?! I tried thinking about such possiblities but did not get
very far.

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Mike, Nick, Julia, Meghan L., Meghan R.
Grade 4
Ms. Seager
Bagnall School, Groveland, MA

The mother needed the 18th horse so she had a number she could divide
evenly by 2, 3, and 9. If you divide 17 by 2, 3, and 9, you end up with
each son getting a fraction of a horse and if you cut a horse up it would
be dead. However, if you divide 17 by 2, 3, and 9, the fractions you get
are greater than one half so if you round them, you get 9, 6, and 2 as your
whole numbers so you really can do the 
problem without 18 horses.

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She needed the eighteenth horse to find the least common multiple of the
fractional amounts so that she divide the horses the way the father said.
She turned 1/2,1/3, and 1/9 into eighteenths. Then she could solve the
problem.

Steve Moleski
Mr. Underkoffler's fifth grade class
Arrowhead School
Methacton School District
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The farmers wife borrowed a horse making the number of horses 18. One half
of 18 is 9, and one third of 18 is 6, and one ninth of 18 is 2. 9+6+2=17,
so she can now give back the neighbor's horse. 
submitted by Mrs. Fisher's fourth/fifth grade class
Aliso School, Carpinteria, California.

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