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Year 2000Date: 07/13/99 at 15:24:15 From: Ben Ewing Subject: Why isn't Y2k a leap year? Why isn't the year 2000 a leap year? Since every year is 365.26 days long, wouldn't every 100 years be a double leap year? Does it have to do with some weird mathamatical process? Thanks. Date: 07/13/99 at 17:07:36 From: Doctor Rick Subject: Re: Why isn't Y2k a leap year? Hi, Ben. I don't know where you got your information, but 2000 _will_ be a leap year. The years 1900 and 1800 and 1700 were not leap years, but 1600 was, and 2000 will be. Here is an interesting Web site with information about the Gregorian calendar (which we use now) and its leap-year rule, which I quote: The Julian and the Gregorian Calendars, by Peter Meyer http://www.magnet.ch/serendipity/hermetic/cal_stud/cal_art.htm "In the Gregorian Calendar a year is a leap year if either (i) it is divisible by 4 but not by 100 or (ii) it is divisible by 400. In other words, a year which is divisible by 4 is a leap year unless it is divisible by 100 but not by 400 (in which case it is not a leap year). Thus the years 1600 and 2000 are leap years, but 1700, 1800, 1900 and 2100 are not." This Web site also differs with you about the length of a year, stating: "The mean solar year during the last 2000 years is 365.242 days (to three decimal places)." It is because this figure is slightly _less_ than 365 1/4 days (not greater, as you stated) that it is necessary to _omit_ occasional leap days (rather than add any). To be precise, 3 days are omitted every 400 years. The average length of a calendar year is thus 365.25 - 3/400 = 365 - 0.0075 = 365.2425, which matches the astronomical figure given above pretty well. If the year were 365.26 days long, your calculation would be correct, we would need to insert an extra leap day every 100 years. The calculations I've described don't seem too weird to me, but the matter of defining exactly what a year is turns out to be pretty complicated, as you will see from this Web site. - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ Date: 07/18/99 at 13:33:28 From: Ben Ewing Subject: Re: Why isn't Y2k a leap year? Thanks, I am skilled in Math and I didn't really mean wierd, sorry 'bout that. I always thought years were 365.26 so it's good to know that they are 365.242. Thanks again. Ben Date: 07/19/99 at 09:14:50 From: Doctor Rick Subject: Re: Why isn't Y2k a leap year? Hi again, Ben. I took no offense at the word "weird"; in fact I wanted to acknowledge that the definitions of year and day do get pretty complex and even weird - though they make sense when you get to know them. I did a quick Web search to verify my hunch about your figure for the length of a year. One site I found has a long list of definitions of various astronomical periods: PREDICTABLE PERIODIC EVENTS (Jan Curtis, Alaska Climate Research Ctr.) http://climate.gi.alaska.edu/Curtis/astro1.html I will quote the relevant sections: "Earth's Tropical year 365.24219 Days "Interval for Earth to return to same equinox. This explains why leap years exist. Leap years also occur only in years when centuries are evenly divisible by four (e.g., 1600, 2000, 2400, etc.). The Gregorian calendar therefore is equal to 365 days 5 hours 49 minutes 12 seconds. "Earth's Sidereal year 365.25636 Days "Interval for Earth to return to same fixed star. "Earth's Anomalistic year 365.25964 Days "Interval for Earth to orbit the Sun as measured from its closest point (perihelion) to its return back. This period is slightly less than five minutes longer than the sidereal year because the position of the perihelion point moves along the Earth's orbit by about 1.1 minutes of arc yearly. During this current epoch, the Earth is closest the Sun just after the new year. It will take about 12,500 years for this date to advance six months." In other words, the length of a year depends on whether you are measuring the time for the earth to return to the same place in orbit relative to the stars (sidereal year), or relative to the direction of the earth's tilt (tropical year), or relative to the perihelion of the earth's orbit (anomalistic year). The figure relevant to the calendar is the tropical year, because it relates to the seasons. The figure you know is correct, but it's one of the other kinds of "year." - Doctor Rick, The Math Forum http://mathforum.org/dr.math/ |
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