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Perimeter of a Reuleaux TriangleDate: 04/15/2001 at 09:49:51 From: deborah crisp Subject: Perimeter of a Reuleaux triangle How can I find perimeter of a Reuleaux triangle of width d? Is the formula circumference = pi times width (d)? This seems too simple.
Date: 04/17/2001 at 14:26:30
From: Doctor Douglas
Subject: Re: Perimeter of a Reuleaux triangle
Hi Deborah, and thanks for writing.
Yes, it does seem simple, but there is a theorem that states that all
curves of constant width d have the same perimeter, pi*d: Barbier's
theorem.
You can verify this theorem directly for the Reuleaux triangle.
Suppose that the diameter of the Reuleaux triangle is d. Each side of
the base equilateral triangle has length d. Then the perimeter of the
Reuleaux triangle is composed of three circular arcs, each of which
has arc length equal to
s = radius * subtended_angle
= d * pi/3 angle is measured in radians
and the total perimeter is
S = 3*s = d*pi
I hope this helps answer your question.
- Doctor Douglas, The Math Forum
http://mathforum.org/dr.math/
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